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What is a probability that the selected card will be an ace if one is missing?
The probability of drawing a Ace from a standard deck of 52 cards if one Ace is missing is 3 in 51, or about 0.05882. If the missing card is not an Ace, then the probability is 4 in 51, or about 0.07843.
Draw a single card from a 52 card deck and not an ace?
Probability not ace is 1 minus probability of an ace which is 4/52. So, 1 - 4/52 is 48/52 or 12/13.
What is the probability of drawing a red number card from a deck of cards?
13 out of 52. _____________________ It should be 20 out of 52 if Ace is included as a number card. Not including ace the probability is 18 out of 52.
What is the probability of drawing 2 cards that are a 2 from a deck of 52 when first card is an ace and 2nd non ace?
The probability of drawing two cards that are a 2 when the first card is an Ace is zero, because a two is not an Ace. They are mutually exclusive events. If this is not clear, consider the probability of rolling a seven on one roll of one six sided die. That probability is also zero - it will not happen.
If The first card is an ace and the second is also an ace what the probility?
Just a straight deal, the first card will be an ace 4 times out of 52, the second card will be an ace 3 times in 51. The total odds will be 12 times in 2652.However in the question posed the first card is an ace so the probability is 1 in 1, so the second card being an ace will occur 3 times in 51.In the question , the first card is ACE, and second is also an ACE. Hence probability is 1in 1.How ever the question should be framed "What is the probabilty for getting first card An ACE and also Second card as An ACE"
