Find the probability of getting a sum of 7 and call that p(7). Now the complement rule says 1-p(7) is the probability of not getting 7.
The ways we get 7 are 1 and 6, or 2 and 5, or 3 and 4.
If you make a table with 1-6 on the top and 1-6 on the side, you can let each entry in your table be the sum of the top row and the side column. Since this is a 6x6 table, you can see
there are 36 outcomes.
6 of those outcome result in a sum of 7.
They are:
1+6
6+1
2+5
5+2
3+4
4+3
So p(7) =6/36 or 1/6. P of not getting 7 is 1-1/6=5/6
The probability is 7/36.
1 in 36
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
The answer depends on how many dice you roll and how often. If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54
The probability of rolling a sum of 12 in a single roll of two dice is 1 in 36, or about 0.0278.
1:6
The probability is 7/36.
1 in 36
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
That depends on what kind of dice you are rolling and how many of them you roll. If you roll two 6-sided dice once, the probability of getting the number 100 is exactly zero. You cannot get a 100 on one roll of two 6-sided dice. Other dice and different numbers of them may yield different probabilities.
The answer depends on how many dice you roll and how often. If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54
The probability of rolling a sum of 12 in a single roll of two dice is 1 in 36, or about 0.0278.
The probability of getting an odd number when you roll one die is 1 in 2. In order to get an odd sum with two dice, one of them has to be odd and one of them has to be even. The probability of rolling an odd sum is still 1 in 2, since each die is unrelated in probability to the other.
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
0.3 * 0.3 = 0.09
The probability of getting a sum of 2 at least once is 0.8155
The probability is 1/6.