For a four digit pin number:
You receive the first PIN number, let's say WXYZ.
The probability that the next pin number you receive would match (assuming they are randomly provided), is:
For each digit, they are 10 possibilities [0 1 2 3 4 5 6 7 8 8]. The probability that one specific number is chosen is thus of 1/10.
For the are four digits, hence four independent selection of one digit, each with a probability of 1/10.
The probability of an event, combination of independent events, is the product of the the probability of the independent event.
Thus, the probability that the next pin number you receive would match (assuming they are randomly provided), is:
1/10*1/10*1/10*1/10 or
1/10^4 or
0.0001 or
1 out 10000
The answer depends on the numbers on the cards in the bag!
The probability of the occurrence of a deck of cards is 1.
Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52
If you draw 9 or fewer cards, the probability is 0. If you draw 10 or more card, the probability is 1.
The probability is 1 - if you pick 40 cards without replacing them.
The probability is approx 0.09. This assumes that J and K are not prime numbers.
The answer depends on the numbers on the cards in the bag!
I'm afraid there's not enough information to answer this question. What are the numbers on the twenty cards exactly? Here's how you can do. Let n = the number of 8s in the 20 cards The probability will just simply be n/20.
The probability of the occurrence of a deck of cards is 1.
1/400
For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.
To play DOS cards, players take turns matching numbers and colors on their cards to the cards in the center of the table. The goal is to be the first to get rid of all your cards. Players can also use special action cards to change the game play.
The rules for playing Uno cards involve matching colors or numbers, playing action cards, and being the first to get rid of all your cards to win. Players take turns drawing and playing cards until someone has no cards left.
Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52
The probability of no player ever getting a pair with 5 players of Texas Hold 'Em in 26 hands is 1.4937 x 10-8, but see the note at the bottom. A five-player game of Texas Hold 'Em has 15 cards in play on each hand; the two down cards for each player, and the 5 common up cards. The probability of one of the down cards matching the other down card or one of the five up cards is 6 in 52 or 0.11538. The probability of one of the up cards matching one of the four other up cards is 4 in 52 or 0.076923. Invert these probabilities, and you get the probability of not matching: 46 in 52 for the down card, and 12 in 13 for the up card. Multiply these two together, and you get the probability of 552 in 676 or 0.81657 that one player does not have a pair. To determine the probability that no player has a pair, include the four other down card probabilities in the calculation. The up card probability is common to all players, so you only count that once. You get a probability of 2471555712 in 4942652416 or 0.50005 that no one has a pair in one game. To determine the probability that no player has a pair in 26 games, simply raise that to the 26th power, giving a probability of 1.4937 x 10-8 (0.000000014937) that no one gets a pair in 26 games. Note that this does not include the probability of someone not getting a flush or straight - it only gives the probability of no one ever getting a pair, and the result is so low as to be practically impossible.
10
If you draw 9 or fewer cards, the probability is 0. If you draw 10 or more card, the probability is 1.