There is insufficient information in the question to answer it. You did not specify how many dice were involved. Please restate the question.
In the meantime, I will give a generalized answer.
If the probability of rolling a straight is n, then the probability of rolling straight three times in a row is n3. For instance, with three dice, the probability of rolling a straight is 1 in 36, neglecting (i.e. allowing for) wrap-around straights, and ignoring (sorry, but the math is too complex and does not serve the answer anyway) the fact that straights can go in either direction. That 1 in 36 is n=0.02778. The probability of doing that 3 times in a row, then, is 0.00002143.
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3 out of 18
The probability of rolling a 3 with a standard die is 1 in 6. The probability of doing that two times in a row is 1 in 6 squared, or 1 in 36.
The probability of rolling an odd number is 3/6 (or rather, 1/2), so the probability of rolling an odd number three times in a row is 1/2^3 is 1/8 or 12.5%.
The probability of rolling a 3 is 1/6.
Even numbers: 2, 4, 6, the probability to get an ven number is 3/6 = 1/2 The probability to get 4 even number in a row is then (1/2)4 = 1/24 = 1 / 16 It is the same probability to get 4 odd numbers (1,3,5) in a row