The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
fifty percent
Probability is a number between 0 and 1. The probability of an event cannot be 12.
10/3
Assuming the die is a standard die with a different number from the set {1, 2, 3, 4, 5, 6} on each side, then: Probability_of_success = number_of_ways_of_success/total_number_of_outcomes There is only 1 way to roll a 4 and there are 6 possible outcomes, therefore the probability of rolling a 4 is 1/6 The die has no knowledge of previous rolls; each roll is independent, thus: The probability of three fours is a row is the probability of a 4 times the probability of a 4 times the probability of a 4, which is: Probability = 1/6 × 1/6 × 1/6 = 1/216
1/8
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
fifty percent
Probability is a number between 0 and 1. The probability of an event cannot be 12.
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
00
10/3
The first number doesn't matter, just that the last three are the same as the first. P(rolling the same as the number before) = 1/6 P(rolling the same number as the first three times = (1/6)3 = 1/216
The probability of rolling a six is one in six. The probability of rolling three consecutive sixes is one in 216. (1/6 x 1/6 x 1/6 = 1/216)
The probability is 1/6 x 5=5/12
Assuming that the die is a "normal" one (it has the numbers 1 to 6 and that it is fair), then the probability of rolling six three times in a row is 1/6*1/6*1/6 = 1/216 = 0.00463 The probability of rolling six three times in a row eventually is 1 (ie a certainty).
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