Assuming it is a normal fair cube, it is 1/6.
That depends on how many sides the cube has but if it was a 6 sided cube then the probability of getting a four is 1 to 6 and even is 3 to 6. Since 4 is even, then the result set of 4 intersect with the result set of even, so the probability of rolling a 4 or an even number is 1 in 2, or 0.5.
The probability of rolling a three or a four (meaning one roll, and either number would be counted a "success") is 1/3. This is because the probability of rolling a three is 1/6, the probability of rolling a four is 1/6, and if you are good with either possibility, then the combined probability is 1/6+1/6 = 1/3.
A standard die has six faces numbered 1 through 6. The factors of 4 are 1, 2, and 4, so there are three favorable outcomes. Therefore, the probability of rolling a factor of four is the number of favorable outcomes (3) divided by the total number of outcomes (6), which is ( \frac{3}{6} ) or ( \frac{1}{2} ). Thus, the probability is 50%.
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
On a standard 6 sided die the probability of rolling four is 1/6 This is because there are 6 different numbers on it, and when you roll it you read only the top number. There are 6 to choose from and all 6 are equally probable, so that probability is 1 out of 6 = 0.1666....(a recurring 6) = 16.67% to 4 significant figures
That depends on how many sides the cube has but if it was a 6 sided cube then the probability of getting a four is 1 to 6 and even is 3 to 6. Since 4 is even, then the result set of 4 intersect with the result set of even, so the probability of rolling a 4 or an even number is 1 in 2, or 0.5.
2/6 or 1/3 or 0.3333.
The probability of rolling a three or a four (meaning one roll, and either number would be counted a "success") is 1/3. This is because the probability of rolling a three is 1/6, the probability of rolling a four is 1/6, and if you are good with either possibility, then the combined probability is 1/6+1/6 = 1/3.
The probability of rolling a four on an eight sided octahedron is 1 in 8, or 0.125.
The probability of rolling a dice with the letters "D," "I," "C," and "E" on all four sides is 1 in 1,296.
There is only one other number higher than five on the standard six sided number cube. That being said, their is only a one in two, or 50% chance that you will roll equal or higher than five. But only if the five and six are what's relative. It you count the numbers one through four, then you only have a two in six, or one in three (33.3%) chance of rolling five or six.
The experimental probability of a number cube that lands on 5 four times in a twenty toss trial is Pexp(5) = 4/20 = 1/5 = 0.20 = 20%
Because we are only modeling one event, all six outcomes of the die are equally possible. The probability of rolling a four (or, for that matter, any number) is 1/6, or .166666 repeating. Now, since we are modeling 120 rolls, the theoretical number of outcomes of four (or, again, any number) is 1/6 * 120 = 20 outcomes. The second sentence of the problem is unnecessary.
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
On a standard 6 sided die the probability of rolling four is 1/6 This is because there are 6 different numbers on it, and when you roll it you read only the top number. There are 6 to choose from and all 6 are equally probable, so that probability is 1 out of 6 = 0.1666....(a recurring 6) = 16.67% to 4 significant figures
The probability of the first one is 1/6 .The probability of the second one is 1/6 .The probability of the third one is 1/6 .The probability of the fourth one is 1/6 .The probability of all four is (1/6)4 = 0.0007716 (rounded) = 0.077 %
The probability of rolling a 4 when you throw once a fair die is: P(4) = 1/6.The probability of not rolling a 4 when you throw once a fair die is: P(NO 4) = 5/6.If you roll a fair die four times, the probability of rolling a four on only the secondthrow is:P(NO 4, 4, NO 4, NO 4) = (5/6)(1/6)(5/6)(5/6) = 0.096450617... ≈ 9.6%