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Determine the probability of the sum of 8 in the single tossed in a pair of fair dice?
The probability of rolling a sum of 8 is approx a 14% chance. There are 36 possibilities when rolling 2 die. There are 5 possibilities of rolling a sum of 8. → Probability = 5/36 = 5/36 x 100% ≈ 14%.
Suppose you roll two number cubes once Use the counting principle to find the probability of rolling a 4 on both cubes?
The probability of rolling 4 and 4 on a single roll of two dice is 1 in 36. You don't have to count. The probability of rolling 4 on one die is 1 in 6. The probability of rolling two 4's is (1 in 6) squared or 1 in 36. If you insist on counting, go ahead, 11, 12, 13, 14, 15, 16, 21, 22, 23, 24, etc. You will find 36 combinations, with only one 44 in them, hence 1 in 36.
question . If two normal dice are thrown together, what is the probability of getting a sum of 6?
5 of 36. That's about 14% if you round up.
How many possible combinations are for only the EVEN numbers in rolling 3 dice in random regular 6 sided dice?
Here are three possible interpretations of the question, with answers:A) How many combinations are possible when when rolling three identical regular dice simultaneously, if all the dice show an even number?Answer: 10 (Originally given by Mehta matics)... (2,2,2) -> 6... (2,2,4) -> 8... (2,2,6), (2,4,4) -> 10... (2,4,6), (4,4,4) -> 12... (2,6,6), 4,4,6) -> 14... (4,6,6) -> 16... (6,6,6)-> 18B) How many combinations result in an even total when rolling three identical regular dice simultaneously?Answer:28... The totals must be between 3 and 18 inclusive.... sum of 4: (1,1,2)... sum of 6: (1,1,4), (1,2,3), (2,2,2)... sum of 8: (1,1,6), (1,2,5), (1,3,4), (2,2,4), (2,3,3)... sum of 10: (1,3,6), (1,4,5), (2,2,6), (2,3,5), (2,4,4), (3,3,4)... sum of 12: (1,5,6), (2,4,6), (2,5,5), (3,3,6), (3,4,5), (4,4,4)... sum of 14: (2,6,6), (3,5,6), (4,4,6), (4,5,5,)... sum of 16: (4,6,6), (5,5,6)... sum of 18: (6,6,6), for a total of 1+3+5+6+6+4+2+1 =28 combinations.C) When rolling three regular dice, how many even totals are possible?Answer: 8... 4, 6, 8, 10, 12, 14, 16, 18.
What is the probability of reading at least 14 of 20 books?
Depends on the probability of reading any.
