A number cube is a six sided figure so I'm going to go with 0%
15
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
When a number cube is rolled twice, there are 36 possible outcomes. (1,1),(1,2),....(6,6). (3,3) occurs only once. Therefore, the probability of rolling a 3 both times is 1/36.
To find the experimental probability of rolling a 6, you first need to determine the number of times a 6 was rolled during the experiment. Then, divide that number by the total number of rolls recorded in the table. The resulting fraction represents the experimental probability of rolling a 6. For example, if a 6 was rolled 5 times out of 30 total rolls, the experimental probability would be 5/30, which simplifies to 1/6.
To determine the experimental probability of rolling a 4, you need to divide the number of times a 4 was rolled by the total number of rolls conducted in the trial. For example, if a 4 was rolled 3 times out of 20 rolls, the experimental probability would be 3/20, or 0.15. This probability reflects the observed outcomes based on the specific trial conducted.
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.
25/36
It is 0.8217
50% chance
The probability of rolling a 6 is 1/6. The probability of rolling 10 times a 6 is (1/6)10 or 1.654X10-8.
The probability of rolling a 5, based on the information given, is 80/375 or 16/75. Your problem describes a relative frequency approximation of probability.