Until the letter is selected, it is a variable. Immediately after it is selected, the outcome is no longer a variable but a constant.
To find the probability of randomly selecting the letters S, N, O, and T in that specific order from the letters in "FOUNDATIONS," we first note that there are 12 letters in total. The probability of selecting S first is 1/12, then N (1/11), O (1/10), and T (1/9). Therefore, the probability of selecting S, N, O, and T in that order is (1/12) * (1/11) * (1/10) * (1/9) = 1/11880, or approximately 0.000084.
The word "mathematics" has 11 letters in total. The consonants in the word are m, t, h, m, t, c, and s, totaling 7 consonants. To find the probability of selecting a consonant, divide the number of consonants (7) by the total number of letters (11), resulting in a probability of 7/11.
It is 21/26.
The probability is 0.
It is 3/4.
The statement about the probability of selecting the letter 'z' from the alphabet being 126 is incorrect. The probability of selecting any one specific letter from the 26 letters of the English alphabet is 1/26, not 126. Therefore, the probability of selecting 'z' is approximately 0.0385, or about 3.85%.
Theoretical
Theoretical
To find the probability of randomly selecting the letters S, N, O, and T in that specific order from the letters in "FOUNDATIONS," we first note that there are 12 letters in total. The probability of selecting S first is 1/12, then N (1/11), O (1/10), and T (1/9). Therefore, the probability of selecting S, N, O, and T in that order is (1/12) * (1/11) * (1/10) * (1/9) = 1/11880, or approximately 0.000084.
The answer depends on what you are selecting from. If you are selecting months in which the equinoces occur, the probability is 0.5
The probability is 1. The letters in the word mathematics are all constants, not variables!
The word "mathematics" has 11 letters in total. The consonants in the word are m, t, h, m, t, c, and s, totaling 7 consonants. To find the probability of selecting a consonant, divide the number of consonants (7) by the total number of letters (11), resulting in a probability of 7/11.
It is 21/26.
If the letters of the word "BULLDOG" are written on paper, there are 7 letters in total: B, U, L, L, D, O, G. Among these, the letter L appears twice. To find the probability of randomly selecting a particular letter square, you would calculate the chance of selecting one specific letter from the total. However, since the question is about the probability of cutting the letters into squares, it is always 100% that you can cut them, making the probability of this event equal to 1.
The probability is 0.4231, approx.
The probability of selecting a red card is 26 in 52 or 1 in 2. The probability of selecting an even card is 20 in 52 or 5 in 13. The probability, therefore, of selecting a red even card is 1 in 2 times 5 in 13 or 5 in 26.
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%