To find the probability of selecting a six, queen, or four from a standard deck of 52 cards, first note that there are four sixes, four queens, and four fours in the deck. Since these events are mutually exclusive, you can add the probabilities together. The total number of favorable outcomes is 4 (sixes) + 4 (queens) + 4 (fours) = 12. Therefore, the probability is 12/52, which simplifies to 3/13 or approximately 0.231.
To calculate the probability of getting at least four heads when flipping a coin six times, we can use the binomial probability formula. The total number of outcomes for six flips is (2^6 = 64). The probabilities for getting exactly four, five, and six heads can be calculated using the binomial formula, and their sum gives the total probability of getting at least four heads. This results in a probability of approximately 0.65625, or 65.625%.
3 out of 7
The probability of four out of six shots is the probability of four successes, times the probability of two failures, times the number of permutations of successes and failures: P(four out of six free throws) = 15 * (2/5)4 * (3/5)2 = (15 * 16 * 9) / (625 * 25) = 432 / 3125
The probability of rolling a two on a six-sided die is determined by the number of favorable outcomes divided by the total number of possible outcomes. There is one favorable outcome (rolling a two) and six possible outcomes (rolling a one, two, three, four, five, or six). Therefore, the probability is 1/6.
The probability of drawing a three, four, five, or six from an ordinary 52 card deck is 4 in 13, or about 0.3077.
To calculate the probability of getting at least four heads when flipping a coin six times, we can use the binomial probability formula. The total number of outcomes for six flips is (2^6 = 64). The probabilities for getting exactly four, five, and six heads can be calculated using the binomial formula, and their sum gives the total probability of getting at least four heads. This results in a probability of approximately 0.65625, or 65.625%.
3 out of 7
The probability of four out of six shots is the probability of four successes, times the probability of two failures, times the number of permutations of successes and failures: P(four out of six free throws) = 15 * (2/5)4 * (3/5)2 = (15 * 16 * 9) / (625 * 25) = 432 / 3125
The probability of rolling a two on a six-sided die is determined by the number of favorable outcomes divided by the total number of possible outcomes. There is one favorable outcome (rolling a two) and six possible outcomes (rolling a one, two, three, four, five, or six). Therefore, the probability is 1/6.
The probability of drawing a three, four, five, or six from an ordinary 52 card deck is 4 in 13, or about 0.3077.
This probability is (1/6)6.
(1 in 6)3 or (1 in 216) or about 0.004630.
the probability is 5/6
P(x=4) ≈ 0.00001847 or about 1 in 54 145The probability of selecting 4 aces while playing poker with six people is:P(x=4) = 5C4 ∙ 4!/[52!/(52-30)!] ∙ (52-4)!/(52-30)!= 5C4 ∙ 4!(52-4)!/52! ≈ 1.846892603... x 10-5 ≈ 0.00001847which is about 1 in 54 145.
There are four 6's in a 52 deck of cards; so probability of drawing a 6 is 4/52 or 1/13 or 0.077
The probability of getting a six on a six sided die and then getting a tails is zero. There is no tails on a die.
i dont know