In a standard deck of 52 playing cards, there are 4 tens and 4 jacks, making a total of 8 favorable outcomes. To find the probability of selecting either a ten or a jack, you divide the number of favorable outcomes (8) by the total number of possible outcomes (52). Therefore, the probability is ( \frac{8}{52} ), which simplifies to ( \frac{2}{13} ).
3 in 52 (jack, queen, king of spades)
The probability is 0.
The probability that the first card is a jack is 4 in 52. The probability that the second card is 1 ten is 4 in 51. Since these are sequential events, simply multiply, giving (4/52)(4/51) or (16/2652) or about 0.00603.
It is 3/4.
P (selecting a king) = 4/52 = 1/13
4 in 52 or 1 in 13
It is 0.7
The answer depends on what you are selecting from. If you are selecting months in which the equinoces occur, the probability is 0.5
3 in 52 (jack, queen, king of spades)
The probability is 0.4231, approx.
The probability of selecting a red card is 26 in 52 or 1 in 2. The probability of selecting an even card is 20 in 52 or 5 in 13. The probability, therefore, of selecting a red even card is 1 in 2 times 5 in 13 or 5 in 26.
The statement about the probability of selecting the letter 'z' from the alphabet being 126 is incorrect. The probability of selecting any one specific letter from the 26 letters of the English alphabet is 1/26, not 126. Therefore, the probability of selecting 'z' is approximately 0.0385, or about 3.85%.
The probability is 0.
The probability that the first card is a jack is 4 in 52. The probability that the second card is 1 ten is 4 in 51. Since these are sequential events, simply multiply, giving (4/52)(4/51) or (16/2652) or about 0.00603.
You randomly select one card from a 52-card deck. Find the probability of selecting the king of diamonds or the jack of
It is 3/4.
The probability is 2:7.