3 in 52 (jack, queen, king of spades)
The probability is 0.
The probability that the first card is a jack is 4 in 52. The probability that the second card is 1 ten is 4 in 51. Since these are sequential events, simply multiply, giving (4/52)(4/51) or (16/2652) or about 0.00603.
It is 3/4.
P (selecting a king) = 4/52 = 1/13
4 in 52 or 1 in 13
It is 0.7
The answer depends on what you are selecting from. If you are selecting months in which the equinoces occur, the probability is 0.5
3 in 52 (jack, queen, king of spades)
The probability is 0.4231, approx.
The probability of selecting a red card is 26 in 52 or 1 in 2. The probability of selecting an even card is 20 in 52 or 5 in 13. The probability, therefore, of selecting a red even card is 1 in 2 times 5 in 13 or 5 in 26.
The probability is 0.
You randomly select one card from a 52-card deck. Find the probability of selecting the king of diamonds or the jack of
The probability that the first card is a jack is 4 in 52. The probability that the second card is 1 ten is 4 in 51. Since these are sequential events, simply multiply, giving (4/52)(4/51) or (16/2652) or about 0.00603.
It is 3/4.
The probability is 2:7.
3 out of 4?