25%
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
Count the total number of ways it can turn out. Count the number of ways that are the condition you're looking for. The probability of the outcome you're looking for is is the second number divided by the first number.
What is the probability of rolling a 6 the first time and a 1 the second time
It is 1/2*1/3 = 1/6
It is 1/12.
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
Count the total number of ways it can turn out. Count the number of ways that are the condition you're looking for. The probability of the outcome you're looking for is is the second number divided by the first number.
The answer depends on whether the first number is replaced before picking the second. If not, the probability is 0.029
What is the probability of rolling a 6 the first time and a 1 the second time
It is 1/2*1/3 = 1/6
It is 1/12.
The probability that the second coin matches the first is 0.5 .The probability that the third coin matches the first is 0.5 .The probability that the second and third coins both match the first is (0.5 x 0.5) = 0.25 = 25%
The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.
The probability when you roll two dice that you roll an odd number on the first die and a 1 on the second die is 1 in 12. The two die are sequentially unrelated, so you can consider them separately. The probability of rolling an odd number is 3 in 6, or 1 in 2. The probability of rolling a 1 is 1 in 6. Multiply the two probabilities together and you get 3 in 36, or 1 in 12.
The number of "favourable" outcomes.
(1/2) * (1/6) = 1/12
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