The probability of 2 coins both landing on heads or both landing on tails is 1/2 because there are 4 possible outcomes. Head, head. Head, tails. Tails, tails. Tails, heads. Tails, heads is different from heads, tails for reasons I am unsure of.
If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you.If a number cube (die) contains the numbers 1, 2, 3, 4, 5, and 6, and the cube is fair, then the probability of rolling a 6 is 1 in 6. If you roll the cube 10 times, you would expect to get 6's 10 / 6, or about 2 times. However, 10 trials is not a lot of trials, so the experimental outcome might not match the theoretical probability. In this case, the experimental probability matched the theoretical probability, but that is simply chance. If you repeat the experiment, so you will probably not get the same results.
The probability that you will roll doubles on a pair of dice is 1 in 6. The probability that you roll "something" on the first die is 1 in 1. The probability that the second die will match the first die is 1 in 6. The resultant probability is simply the product of (1 in 1) and (1 in 6).
It is often a "goodness of fit" test. This is a test of how well the observations match the frequencies that would have been expected on theoretical basis. The theoretical basis may simply be your hypothesis.
Out of the six faces, only 3 and 5 match the requirements, so the probability is 2/6 or 1/3.
None of the experimental probabilities need match the corresponding theoretical probabilities exactly.
The probability of 2 coins both landing on heads or both landing on tails is 1/2 because there are 4 possible outcomes. Head, head. Head, tails. Tails, tails. Tails, heads. Tails, heads is different from heads, tails for reasons I am unsure of.
The word "experimental" is usually used to describe data that have come from an actual test or experiment. These data are opposite to "theoretical" data, which are only educated guesses at what the data should look like. In statistics, theoretical probability is used a lot. For example, if I flip a coin, in theory, it would land on each side half of the time. Perform some trials, however, and this percentage may be skewed. The experimental data that you collect probably wouldn't exactly match the theoretical probability.
Assuming I've understood your question properly...First, the number of coins doesn't matter in the slightest; only the first and last count, so the ones in between are irrelevant.Second, the first coin sort of doesn't matter. The only thing that matters is whether or not the last one matches it. Whatever the first coin is, the last coin could come up matching it or, with equal probability, come up not matching it.So the probability is 0.5.If you really want to convince yourself of this, list all the ways the coins could land (HHHH, HHHT, and so on to TTTT). There will be 16 of them. For 8 of those sixteen, the first and last coins will match.
The probability is 1/36
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
The more samples you use, the closer your results will match probability.
0% Everton are woeful.
If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you.If a number cube (die) contains the numbers 1, 2, 3, 4, 5, and 6, and the cube is fair, then the probability of rolling a 6 is 1 in 6. If you roll the cube 10 times, you would expect to get 6's 10 / 6, or about 2 times. However, 10 trials is not a lot of trials, so the experimental outcome might not match the theoretical probability. In this case, the experimental probability matched the theoretical probability, but that is simply chance. If you repeat the experiment, so you will probably not get the same results.
Ok, I'm admittedly not a probability geek, but here is my reasoning... if you flip two coins there are only two possibilities... alike or different, and that's 1 in 2 or 50/50 odds. When you add the third coin it's automatically going to match at least one of the other two... unless the other two were alike and it falls differently. so it does decrease the probability of all matching, and there are three opportunities for one of the coins to be different. So I say it's 1 in 3.
the probability that the school team wins their next hockey match is 0.8. what is the probability that in their next 2 matches the school team a) wins both matches? b) wins neither match? thats wat i wanna know
The probability that you will roll doubles on a pair of dice is 1 in 6. The probability that you roll "something" on the first die is 1 in 1. The probability that the second die will match the first die is 1 in 6. The resultant probability is simply the product of (1 in 1) and (1 in 6).