It depends on how many times you throw it! On a single throw, the answer is 0.5
Depends on the dice! There are six sides on a dice. The number 1 is on on out of the six sides to the probability of getting a one is 1/6 which is equal to .16666 or 16.6%
It is 0.347, approx.
The experimental probability for the die in question is 12/80 = 0.15
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
1 out of 2.
It is a probability of a 1 in 6
It depends on how many times you throw it! On a single throw, the answer is 0.5
The probability of throwing a dice an getting a 1 is 1/6. The probability of gettinga 1 the second time is 1/6. The probability of both events, getting a 1 the firsttime and a 1 the second time is; P(1,1) =(1/6)∙(1/6) =1/36 =0.02777... ~ 2.8%
Depends on the dice! There are six sides on a dice. The number 1 is on on out of the six sides to the probability of getting a one is 1/6 which is equal to .16666 or 16.6%
It is 0.347, approx.
The experimental probability for the die in question is 12/80 = 0.15
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
probability of throwing a '6' on a single die: 1/6probability of throwing six on a pair of dice: 5/36
1 out of 6 times,or 16.67% probability.
50%
1 out of 6