The probability of throwing just one one with two dice can be calculated by considering the different ways it can occur. There are two ways to get one one: rolling a one on the first die and any number on the second die, or rolling any number on the first die and a one on the second die. There are a total of 36 possible outcomes when rolling two dice, so the probability is 2/36, which simplifies to 1/18.
You have more chance with two dice rolled together ! The Probability of throwing a six with one dice is 1/6. The probability of throwing one six with two dice is 2/6 or 1/3. You're twice as likely to score a six if you're throwing two dice.
Depends on the dice! There are six sides on a dice. The number 1 is on on out of the six sides to the probability of getting a one is 1/6 which is equal to .16666 or 16.6%
1 in 12
It is 0.347, approx.
A normal die is a six faced cube, so the probability of each face coming up is one in six and there are six possible outcomes. If you throw two dice, then there are 36 (6x6) possible outcomes, and you would simply divide the desired result set by the possible result set. For instance, the probability of throwing a 12 is 1 in 36, while the probability of throwing an 11 is 2 in 36 or 1 in 18 because there are two ways to throw the 11. Similarly, the probability of throwing a 7 is 6 in 36 or 1 in 6, because there are 6 different ways to throw a 7. Continuing with more and more dice, it is a simple matter of counting and arithmetic.
You have more chance with two dice rolled together ! The Probability of throwing a six with one dice is 1/6. The probability of throwing one six with two dice is 2/6 or 1/3. You're twice as likely to score a six if you're throwing two dice.
Depends on the dice! There are six sides on a dice. The number 1 is on on out of the six sides to the probability of getting a one is 1/6 which is equal to .16666 or 16.6%
1 in 12
It is 0.347, approx.
The probability of throwing a dice an getting a 1 is 1/6. The probability of gettinga 1 the second time is 1/6. The probability of both events, getting a 1 the firsttime and a 1 the second time is; P(1,1) =(1/6)∙(1/6) =1/36 =0.02777... ~ 2.8%
This equates to throwing ten fives. The probability of throwing one five with one die is (of course) one sixth. We multiply the ten independent probabilities to obtain the overall probability, about one in sixty million: (1/6)10 = 1/610 = 1 / 60466176
The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.
With one roll of three dice, the probability is 7/8.
In this case, you should first calculate the probability of NOT rolling either a 3 or a 6. For one die, this probability is 4/6 = 2/3. For two dice, this probability is 2/3 x 2/3 = 4/9. Therefore, the probability that you DO get a 3 or a 6 is 1 - 4/9 = 5/9.
A normal die is a six faced cube, so the probability of each face coming up is one in six and there are six possible outcomes. If you throw two dice, then there are 36 (6x6) possible outcomes, and you would simply divide the desired result set by the possible result set. For instance, the probability of throwing a 12 is 1 in 36, while the probability of throwing an 11 is 2 in 36 or 1 in 18 because there are two ways to throw the 11. Similarly, the probability of throwing a 7 is 6 in 36 or 1 in 6, because there are 6 different ways to throw a 7. Continuing with more and more dice, it is a simple matter of counting and arithmetic.
probability is 1/6, or unlikely
If you roll them often enough then the probability is 0. For just one roll, the probability is 35/36.