each time he flips a coin he has a one out of two chance it will be tails. so that is 1/2 or .5 percent. you would then multiply that number by iteself twice to get .125
.5 or 50% probability (if not counting draws)
75 over 2^23 (2 times itself 23 times, 2x2x2x2x2 etc...)
The probability to get heads once is 1/2 as the coin is fair The probability to get heads twice is 1/2x1/2 The probability to get heads three times is 1/2x1/2x1/2 The probability to get tails once is 1/2 The probability to get tails 5 times is (1/2)5 So the probability to get 3 heads when the coin is tossed 8 times is (1/2)3(1/2)5=(1/2)8 = 1/256 If you read carefully you'll understand that 3 heads and 5 tails has the same probability than any other outcome = 1/256 As the coin is fair, each side has the same probability to appear So the probability to get 3 heads and 5 tails is the same as getting for instance 8 heads or 8 tails or 1 tails and 7 heads, and so on
Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in Tails exactly twice?The three possible (winning) outcomes are:TTHTHTHTTThe other (losing) outcomes are:HHHHHTHTHTHHTTTSo there is a 3 in 8 chance or a probability of 3/8 = 0.375
The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.
The probability of getting two tails when tossing a coin is zero, because the coin can only have one result. If, one the other hand, you toss the coin twice, then the probability of getting two tails is 0.25, i.e. the probability of one tail, 0.5, squared.
4C2(1/2)4 = 6/16 = 3/8
75%
The probability is 1/2 if the coin is flipped only twice. As the number of flips increases, the probability approaches 1.
The probability is 3/8.
Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in heads exactly twice? This is a pretty easy question to answer. The three possible (winning) outcomes are: 1. Heads, Heads, Tails. 2. Heads, Tails, Heads. 3. Tails, Heads, Heads. If we look at the possible combination of other (losing) outcomes, we can easily determine the probability: 4. Heads, Heads, Heads. 5. Tails, Tails, Heads. 6. Tails, Heads, Tails. 7. Heads, Tails, Tails. 8. Tails, Tails, Tails. This means that to throw heads twice in 3 flips, we have a 3 in 8 chance. This is because there are 3 winning possibilities out of a total of 8 winning and losing possibilities.
It is 0.25
fifty fifty
each time he flips a coin he has a one out of two chance it will be tails. so that is 1/2 or .5 percent. you would then multiply that number by iteself twice to get .125
The probability to get tails once is 1/2 (for a fair coin) The probability to get tails twice = the probability to get it once x the probability to get it a second time The probability to get tails 4 times in a row is (1/2)4=1/16 The probability to get tails n times in a row is (1/2)n=1/2n The same thing is also true for heads (same probability: 1/2 each time)
The probability of getting zero tails is 1/2. The probability of getting zero tails twice in a row is 1/2 x 1/2 = 1/4. The probability of getting zero tails three times in a row is 1/2 x 1/2 x 1/2 = 1/8, etc... .