It depends on how well you pack it, how good a condition it is in, and on how correctly you use it.
In practice, the probability is very low. About one in every 100,000 jumps in the US results in a fatality, a probability of about 0.00001, but that's not just due to parachute failure. One unconfirmed estimate is that one in a thousand (0.001) main chute deployments result in a malfunction, but it is true that very few of those result in a fatality, primarily because there is a reserve chute that is maintained and packed under different, more stringent, requirements.
If the probability of succeeding is 2%, then the probability of failing is 98%. The probability, then, of failing 75 times is 98%75, which is 22%.
Probability of failing to reject a false null hypothesis.
Assuming the alternator's failures are unrelated, the probability of both failing is the product of the individual probability, or 0.022, or 0.0004. The duration of the flight does not matter.
In hypothesis testing, this is the probability of failing to reject a false null hypothesis.
Any time there are two options, heads or tails when you flip a coin for example, the probability is 1/2, that the result will be either one option, or the other. The expected result when the coin lands is a 1/2 probability that it will be heads, and a 1/2 probability that it will be tails. What "1 out of 2 failing" means is that for every two students that take an exam, for example, one of them will fail. Of course, it also means, that 1/2 will pass.
If the probability of succeeding is 2%, then the probability of failing is 98%. The probability, then, of failing 75 times is 98%75, which is 22%.
This question cannot be answered for two reasons.The questions states that "... the probability of each failing [is] 2 ...". That is not possible since probabilities can never be greater than 1.The question does not specify what even the probability is required for: the guidance system failing or not failing!
P(one failing) = 0.02P(one not failing) = 1-0.02 = 0.98P(whole string NOT failing) = 0.9820P(whole string failing) = 1-P(whole string NOT failing) = 0.3324
Probability of failing to reject a false null hypothesis.
Assuming the alternator's failures are unrelated, the probability of both failing is the product of the individual probability, or 0.022, or 0.0004. The duration of the flight does not matter.
In hypothesis testing, this is the probability of failing to reject a false null hypothesis.
Seems like the probability for a single shot is 0.6 So the probability of success with shot 1 is 0.6 and the probability of failing with the first and winning with the second is 0.4x0.6=0.24, same for the other way around, and the probability if winning both times is 0.6x0.6=0.36, and the probability of failing both times is 0.4x0.4=0.16, which is the same as (1-2x.24-.36) Multiply the probability by 100 to get percent.
Technical risk.
Any time there are two options, heads or tails when you flip a coin for example, the probability is 1/2, that the result will be either one option, or the other. The expected result when the coin lands is a 1/2 probability that it will be heads, and a 1/2 probability that it will be tails. What "1 out of 2 failing" means is that for every two students that take an exam, for example, one of them will fail. Of course, it also means, that 1/2 will pass.
Two alternators are used as a safety measure. The probability of both alternator failing are very minimal. Many planes use redundant systems.
If the two switches operate independently and there is no correlation between their failures, then the probability of both switches going bad at the same time would be the product of their individual failure probabilities. So if each switch has a 10% chance of failing, the probability of both failing simultaneously would be 1% (0.10 * 0.10 = 0.01).
a small parachute, is a small parachute, ther is no technical name for it. :) a small parachute is called a drogue