there are 6 faces of the dice so the answer is 1/6
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.
The probability is very, very small, because there are no heads marked anywhere on the dice.
The sample space contains 36 possible outcomes (1,1 & 1,2 & 1,3.....etc up to 6,6). Since 6,6 is the only way to get the sum of 12, the probability of 12 is 1/36.
there are 6 faces of the dice so the answer is 1/6
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
These are independent one has no bearing on the other
1/6 because there are six sides to a dice and we already know the coin landed tails up so that takes that equation out of the picture. otherwise we would be left with figuring the probability of the coin and the dice, but since the question tells us that the coin landed tails up the answer will then be 1/6
Each die can come up in 6 ways.You get exactly 2 only if both dice come up as a ' 1 '.The probability of the first one coming up '1' is (1/6).The probability of the second one coming up as a '1' is (1/6).The probability of both coming up as '1' is (1/6 x 1/6) = (1/36) = 2.78% (rounded)
If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.
The probability is very, very small, because there are no heads marked anywhere on the dice.
The sample space contains 36 possible outcomes (1,1 & 1,2 & 1,3.....etc up to 6,6). Since 6,6 is the only way to get the sum of 12, the probability of 12 is 1/36.
If one die comes up 6, the other must come up 3 or more. So 50%
Assuming you meant a standard pair of dice, only 1 and 1 add to 2, since there are no negatives, and numbers only stretch up to 6, and due to that, there is no 0. Therefore, 1/36 is the probability (probability of rolling a 1, 1/6, probability of rolling a 1, 1/6, 1/6(1/6) = 1/36).
The addition rule of probability states that the probability that one or the other will happen is the probability of one plus the probability of the other. This rule only applies to mutually exclusive events. For example, the probability that a dice roll will be a 3 is 1/6. The probability that the dice roll will be even is 1/2. These are mutually exclusive events as the dice cannot be both 3 and even. Thus the probability of the dice roll coming up either a 3, or even, is 1/2 + 1/6 = 2/3.
The probability that there will be EXACTLY one five when four dice are rolled is 500/1296 = 125/324, or about 38.58%. The odds are 199 to 125 against, or about 8 to 5. The probability that there will be AT LEAST one five when four dice are rolled is 671/1296, or about 51.77%. The odds are 625 to 671 against, or about 14 to 15.