If the die is fair, then 1/6.
there are 6 faces of the dice so the answer is 1/6
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.
The probability is very, very small, because there are no heads marked anywhere on the dice.
The sample space contains 36 possible outcomes (1,1 & 1,2 & 1,3.....etc up to 6,6). Since 6,6 is the only way to get the sum of 12, the probability of 12 is 1/36.
there are 6 faces of the dice so the answer is 1/6
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
These are independent one has no bearing on the other
1/6 because there are six sides to a dice and we already know the coin landed tails up so that takes that equation out of the picture. otherwise we would be left with figuring the probability of the coin and the dice, but since the question tells us that the coin landed tails up the answer will then be 1/6
Each die can come up in 6 ways.You get exactly 2 only if both dice come up as a ' 1 '.The probability of the first one coming up '1' is (1/6).The probability of the second one coming up as a '1' is (1/6).The probability of both coming up as '1' is (1/6 x 1/6) = (1/36) = 2.78% (rounded)
If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.
The probability is very, very small, because there are no heads marked anywhere on the dice.
The sample space contains 36 possible outcomes (1,1 & 1,2 & 1,3.....etc up to 6,6). Since 6,6 is the only way to get the sum of 12, the probability of 12 is 1/36.
If one die comes up 6, the other must come up 3 or more. So 50%
Assuming you meant a standard pair of dice, only 1 and 1 add to 2, since there are no negatives, and numbers only stretch up to 6, and due to that, there is no 0. Therefore, 1/36 is the probability (probability of rolling a 1, 1/6, probability of rolling a 1, 1/6, 1/6(1/6) = 1/36).
The probability that there will be EXACTLY one five when four dice are rolled is 500/1296 = 125/324, or about 38.58%. The odds are 199 to 125 against, or about 8 to 5. The probability that there will be AT LEAST one five when four dice are rolled is 671/1296, or about 51.77%. The odds are 625 to 671 against, or about 14 to 15.
There are 36 permutations of two dice. Of these, six have a sum of seven. The probability, then, of rolling a seven on two dice is 6 in 36, or 1 in 6, or about 0.1667.It does not matter if two dice are rolled one time, or if one die is rolled two times. The probability of rolling a sum of 7 is still about 0.1667.The first thing to do is to identify all possible combinations which could give the sum of 7. These are: 6 and 1, 5 and 2, 4 and 3, 3 and 4, 2 and 5, and 1 and 6.Thus there are 6 possible combinations.For each of these combinations, the probability of getting the 1st number correct is 1/6 and the probability of getting the second number correct is 1/6, and so the overall probability of the combination is 1/36There are 6 ways to get 7 though so 6x 1/36 = 1/6Which means the probability that 2 dice rolls will add up to 7 is 1/6