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Q: What is the probability that 4 comes up when a dice is rolled?

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The probability is very, very small, because there are no heads marked anywhere on the dice.

If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.

The sample space contains 36 possible outcomes (1,1 & 1,2 & 1,3.....etc up to 6,6). Since 6,6 is the only way to get the sum of 12, the probability of 12 is 1/36.

With fair regular dice, the answer is 4/36 = 1/9

There are 6 outcomes, a 2 is one of them so the probability is 1/6.

Related questions

there are 6 faces of the dice so the answer is 1/6

If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.

These are independent one has no bearing on the other

1/6 because there are six sides to a dice and we already know the coin landed tails up so that takes that equation out of the picture. otherwise we would be left with figuring the probability of the coin and the dice, but since the question tells us that the coin landed tails up the answer will then be 1/6

Each die can come up in 6 ways.You get exactly 2 only if both dice come up as a ' 1 '.The probability of the first one coming up '1' is (1/6).The probability of the second one coming up as a '1' is (1/6).The probability of both coming up as '1' is (1/6 x 1/6) = (1/36) = 2.78% (rounded)

The probability is very, very small, because there are no heads marked anywhere on the dice.

If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.

If one die comes up 6, the other must come up 3 or more. So 50%

The sample space contains 36 possible outcomes (1,1 & 1,2 & 1,3.....etc up to 6,6). Since 6,6 is the only way to get the sum of 12, the probability of 12 is 1/36.

The addition rule of probability states that the probability that one or the other will happen is the probability of one plus the probability of the other. This rule only applies to mutually exclusive events. For example, the probability that a dice roll will be a 3 is 1/6. The probability that the dice roll will be even is 1/2. These are mutually exclusive events as the dice cannot be both 3 and even. Thus the probability of the dice roll coming up either a 3, or even, is 1/2 + 1/6 = 2/3.

Assuming you meant a standard pair of dice, only 1 and 1 add to 2, since there are no negatives, and numbers only stretch up to 6, and due to that, there is no 0. Therefore, 1/36 is the probability (probability of rolling a 1, 1/6, probability of rolling a 1, 1/6, 1/6(1/6) = 1/36).

With fair regular dice, the answer is 4/36 = 1/9

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