Assuming you meant a standard pair of dice, only 1 and 1 add to 2, since there are no negatives, and numbers only stretch up to 6, and due to that, there is no 0. Therefore, 1/36 is the probability (probability of rolling a 1, 1/6, probability of rolling a 1, 1/6, 1/6(1/6) = 1/36).
7
If the order of the dice is irrelevant, then the answer is 21. If the order of the dice is relevant, the answer is 36.
The probability to get a 12, with two dice, is 1/36.
The expected value is 7.
It is 5/36.
If the dice are fair then it is 5/36.
It is 1/9.
7
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
If the order of the dice is irrelevant, then the answer is 21. If the order of the dice is relevant, the answer is 36.
The probability to get a 12, with two dice, is 1/36.
The expected value is 7.
There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
It is 5/36.
One out of six... or however many sides your dice have on it.
Prob = 4/36 = 1/9
Assuming that these number cubes are ordinary dice (number are 1-6) and that both dice are balanced (equal chances for each side to turn up), then it's 1/36. There are 36 different possibilites for the upturned faces when a pair of dice is rolled, one of which is "4 and 4".