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a and b both have the probability of 3/4
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a:b, a/b, a to b
The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%
The answer depends on whether A and B can occur together, that is, if they are mutually exclusive.