Q: What is the probability of the spinner landind on B then C?

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The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%

There are 34 ie 81 possibilities: B appears exactly twice in 18 of these: AABB, ABAB, ABBA, ABBC,ABCB, ACBB, BABA, BABC, BBAA, BBAC, BCAB, BCCB, CABB,CBAB, CBBA, CBBC, CCBA and CCBB.B comes up exactly twice in 18 of the 81 possibilities so probability = 18/81 = 0.22 or 22.2%

The probability density function for a beta distribution with parameters a and b (a, b > 0) is of the form:B(x; a, b) = c*x*(a-1)*(1-x)(b-1) where 0 <= x <= 1. c is a constant such that the integral is 1 and it can be shown that c = G(a+b)/[G(a)*G(b)] where G is the Gamma function.

The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26

The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a

Related questions

the probability would be 1/3

b is incorrect while c is virtually meaningless.

The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%

1 in 5

There are 34 ie 81 possibilities: B appears exactly twice in 18 of these: AABB, ABAB, ABBA, ABBC,ABCB, ACBB, BABA, BABC, BBAA, BBAC, BCAB, BCCB, CABB,CBAB, CBBA, CBBC, CCBA and CCBB.B comes up exactly twice in 18 of the 81 possibilities so probability = 18/81 = 0.22 or 22.2%

60

It is 0.25

The answer requires more information about the context.

The probability density function for a beta distribution with parameters a and b (a, b > 0) is of the form:B(x; a, b) = c*x*(a-1)*(1-x)(b-1) where 0 <= x <= 1. c is a constant such that the integral is 1 and it can be shown that c = G(a+b)/[G(a)*G(b)] where G is the Gamma function.

Let X and Y be two random variables.Case (1) - Discrete CaseIf P(X = x) denotes the probability that the random variable X takes the value x, then the joint probability of X and Y is P(X = x and Y = y).Case (2) - Continuous CaseIf P(a < X < b) is the probability of the random variable X taking a value in the real interval (a, b), then the joint probability of X and Y is P(a < X< b and c < Y < d).Basically joint probability is the probability of two events happening (or not).

The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26

(b b b)( b b b )(b d g a)(b....)(c c c c)(c b b b)(a a a b)(a...d)(b b b)(b b b)(b d g a)(b....)(c c c c)(c b b b)(d d c a)(g.....)