To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%
There are 34 ie 81 possibilities: B appears exactly twice in 18 of these: AABB, ABAB, ABBA, ABBC,ABCB, ACBB, BABA, BABC, BBAA, BBAC, BCAB, BCCB, CABB,CBAB, CBBA, CBBC, CCBA and CCBB.B comes up exactly twice in 18 of the 81 possibilities so probability = 18/81 = 0.22 or 22.2%
The probability density function for a beta distribution with parameters a and b (a, b > 0) is of the form:B(x; a, b) = c*x*(a-1)*(1-x)(b-1) where 0 <= x <= 1. c is a constant such that the integral is 1 and it can be shown that c = G(a+b)/[G(a)*G(b)] where G is the Gamma function.
The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26
The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a
the probability would be 1/3
b is incorrect while c is virtually meaningless.
The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%
There are 34 ie 81 possibilities: B appears exactly twice in 18 of these: AABB, ABAB, ABBA, ABBC,ABCB, ACBB, BABA, BABC, BBAA, BBAC, BCAB, BCCB, CABB,CBAB, CBBA, CBBC, CCBA and CCBB.B comes up exactly twice in 18 of the 81 possibilities so probability = 18/81 = 0.22 or 22.2%
60
It is 0.25
The answer requires more information about the context.
The probability density function for a beta distribution with parameters a and b (a, b > 0) is of the form:B(x; a, b) = c*x*(a-1)*(1-x)(b-1) where 0 <= x <= 1. c is a constant such that the integral is 1 and it can be shown that c = G(a+b)/[G(a)*G(b)] where G is the Gamma function.
Let X and Y be two random variables.Case (1) - Discrete CaseIf P(X = x) denotes the probability that the random variable X takes the value x, then the joint probability of X and Y is P(X = x and Y = y).Case (2) - Continuous CaseIf P(a < X < b) is the probability of the random variable X taking a value in the real interval (a, b), then the joint probability of X and Y is P(a < X< b and c < Y < d).Basically joint probability is the probability of two events happening (or not).
The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26
(b b b)( b b b )(b d g a)(b....)(c c c c)(c b b b)(a a a b)(a...d)(b b b)(b b b)(b d g a)(b....)(c c c c)(c b b b)(d d c a)(g.....)
The answer will depend on how man divisions the spinner has and how many of them are labelled c. Since you have chosen not to share this information the question cannot be answered.