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Five coin flips. Any outcome on a six-sided die has a probability of 1 in 6. If I assume that the order of the outcome does not matter, the same probability can be achieved with five flips of the coin. The possible outcomes of five flips of a coin are as follows: 5 Heads 5 Tails 4 Heads and 1 Tails 4 Tails and 1 Heads 3 Heads and 2 Tails 3 Tails and 2 Heads For six possible outcomes.
The probability of getting a six on a six sided die and then getting a tails is zero. There is no tails on a die.
Prob(Coin shows H) = 1/2 Prob(Die shows 2) = 1/6 Prob(Both events) = 1/2 * 1/6 (because they are independent) = 1/12
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
1/6 * 1/2 = 1/12
3
The probability to tossing a coin and obtaining tails is 0.5. Rolling a die has nothing to do with this outcome - it is unrelated.
probability of tails on a coin is 1/2 probablility of 6 on a die is 1/6
9/2
The probability of flipping tails on a perfect coin in a perfect toss is 0.5. The probability of rolling 1 on a die is 1 in 6. Likewise, the probability of rolling 6 on a die is 1 in 6. So the probability of rolling either 1 or 6 is 2 in 6 (which is 1 in 3).
Five coin flips. Any outcome on a six-sided die has a probability of 1 in 6. If I assume that the order of the outcome does not matter, the same probability can be achieved with five flips of the coin. The possible outcomes of five flips of a coin are as follows: 5 Heads 5 Tails 4 Heads and 1 Tails 4 Tails and 1 Heads 3 Heads and 2 Tails 3 Tails and 2 Heads For six possible outcomes.
The probability of getting a six on a six sided die and then getting a tails is zero. There is no tails on a die.
Prob(Coin shows H) = 1/2 Prob(Die shows 2) = 1/6 Prob(Both events) = 1/2 * 1/6 (because they are independent) = 1/12
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
(1,2,3,4,5,6][Heads,Tails] is a depiction of this notation. It is an expression of probability.
7-12
1/6 * 1/2 = 1/12