The probability is1 - [Prob(No children) + Prob(1 child, a girl) + Prob(2 children, both girls) + Prob(3 children, all girls) + ...]
Not all relevant information is readily available.
Chat with our AI personalities
The probability of a boy is still 0.5 no matter how many prior children there are.
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
The 8 possible outcomes for three children are: * ggg * ggb * gbg * gbb * bgg * bgb * bbg * bbb Of these, two girls and a boy occurs 3 out of 8 times, which is a probability of 0.375. This assumes that the probability of a boy and girl being in the family is equal, which is not entirely true for a large number of reasons.
Assuming the probability of a boy is 0.5, the probability of a boy and boy and boy is 0.5 * 0.5 * 0.5 = 0.125.
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.