The probability of a boy is still 0.5 no matter how many prior children there are.
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
The 8 possible outcomes for three children are: * ggg * ggb * gbg * gbb * bgg * bgb * bbg * bbb Of these, two girls and a boy occurs 3 out of 8 times, which is a probability of 0.375. This assumes that the probability of a boy and girl being in the family is equal, which is not entirely true for a large number of reasons.
Assuming the probability of a boy is 0.5, the probability of a boy and boy and boy is 0.5 * 0.5 * 0.5 = 0.125.
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
The probability of a boy is still 0.5 no matter how many prior children there are.
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
1 in 2
1/4
The 8 possible outcomes for three children are: * ggg * ggb * gbg * gbb * bgg * bgb * bbg * bbb Of these, two girls and a boy occurs 3 out of 8 times, which is a probability of 0.375. This assumes that the probability of a boy and girl being in the family is equal, which is not entirely true for a large number of reasons.
Assuming the probability of a boy is 0.5, the probability of a boy and boy and boy is 0.5 * 0.5 * 0.5 = 0.125.
http://answerboard.cramster.com/statistics-and-probability-topic-5-292446-0.aspx
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
2/4
The probability of a boy (male) is equal to the probability of a girl (female) which equals 1/2. The king is a male. So, we need the probability of a male and a male which is 1/2 * 1/2 = 1/4.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 13 boys in a family with 13 children is approx 0.00019.
There is no simple answer to the question because children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the answer is 0.2331.