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The probability is very close to 0.25

A year is a leap year

if the number is divisible by 4 - except

if the number is divisible by 100 it is not a leap year - except

if the number is divisible by 400 it is a leap year.

So, in a 400-year period there are 97 leap years. The probability or relative frequency of leap years is, therefore, 97/400 = 0.2425

Q: What is the probability that a year selected at random is a leap year with explanation?

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probability = 2/7 to be exact, 28/97 (about 28.87%)

None of them. The probability of an event cannot be greater than one. Besides, every leap year will have 366 days, not 53!

If you assume that birth dates are uniformly distributed over the year (they are not), and you ignore leap years, then the probability of two people selected at random, share a birthday is 1/365.

A Leap year has 366 days. in which you have 52 weeks and 2 days. the 2 days may be sun,Mon mon,Tue tue,wed wed,THu, thu,Fri FRi,SAT sat,sun so you have 7 options among which 2 u can choose.. so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7. The probability of having either 53 Sundays or 53 Thursdays is 4/7.

The total number of days in a leap year is 366. Then, if we want to determine the probability of 53 Wednesdays occurring in a leap year, we write 53 / 366.

Related questions

probability = 2/7 to be exact, 28/97 (about 28.87%)

The probability that a year selected at random will be a leap year is 0.25.

None of them. The probability of an event cannot be greater than one. Besides, every leap year will have 366 days, not 53!

If you assume that birth dates are uniformly distributed over the year (they are not), and you ignore leap years, then the probability of two people selected at random, share a birthday is 1/365.

The probability that a date picked at random is February 30th is zero, as there is no February 30th, even in leap years.

Since you are selecting only among leap years, either the first or the second day of the year would have to be a Saturday, so you have two chances out of seven (a probability of 2/7) that there are 53 saturdays.

28.87% (28/97)

You are guaranteed to have Sundays in a leap year, so in probability terms that is 1.

A Leap year has 366 days. in which you have 52 weeks and 2 days. the 2 days may be sun,Mon mon,Tue tue,wed wed,THu, thu,Fri FRi,SAT sat,sun so you have 7 options among which 2 u can choose.. so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7. The probability of having either 53 Sundays or 53 Thursdays is 4/7.

The total number of days in a leap year is 366. Then, if we want to determine the probability of 53 Wednesdays occurring in a leap year, we write 53 / 366.

100%

Leaving aside leap years, the probability is 0.0137