Q: What is the probability that all 3 tosses will result in heads?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.

With 5 coin tosses there are 32 possible outcomes. 10 of these have exactly 2 heads, and 26 of these have 2 or more heads.For exactly two coins are heads: 10/32 = 31.25%For two or more heads: 26/32 = 81.25%

The chance is 50%-50% that it will be heads or tails; this does not change regardless of the number of previous tosses and their results.

For each toss, the probability that it'll land heads up is 1/2 So 1/2 * 1/2 * 1/2 = 1/8, or .125 There is a 12.5% chance that it will land heads-up all 3 times.

To find P( at least 1 head in 7 tosses) we can find P( no heads) and subtract that from one. Alternatively, we need to find P ( 1 head) + P ( 2 heads )+...+ P(7 heads) Since P of no heads is P( all tails) this is (1/2)7 =.0078125 ( 1/128 as a fraction) Now 1-(1/128)=127/128 or .9921875

Related questions

The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.

The probability of tossing heads on all of the first six tosses of a fair coin is 0.56, or 0.015625. The probability of tossing heads on at least one of the first six tosses of a fair coin is 1 - 0.56, or 0.984375.

If the coin is fair, the probability of getting all heads will decrease exponentially towards 0.

With 5 coin tosses there are 32 possible outcomes. 10 of these have exactly 2 heads, and 26 of these have 2 or more heads.For exactly two coins are heads: 10/32 = 31.25%For two or more heads: 26/32 = 81.25%

The chance is 50%-50% that it will be heads or tails; this does not change regardless of the number of previous tosses and their results.

For each toss, the probability that it'll land heads up is 1/2 So 1/2 * 1/2 * 1/2 = 1/8, or .125 There is a 12.5% chance that it will land heads-up all 3 times.

1/2 x 1/2 x 1/2 = 1/8 The probability is 1 chance in 8 sequences, or .125

0.5*0.5*0.5 = 0.125 or 1/2*1/2*1/2 = 1/8

To find P( at least 1 head in 7 tosses) we can find P( no heads) and subtract that from one. Alternatively, we need to find P ( 1 head) + P ( 2 heads )+...+ P(7 heads) Since P of no heads is P( all tails) this is (1/2)7 =.0078125 ( 1/128 as a fraction) Now 1-(1/128)=127/128 or .9921875

The probability of getting all heads is 1/24 = 1/16 The probability of getting all tails is also 1/24 = 1/16 The probability of all heads or all tails is the sum of the two = 1/8

50-50. each toss is independent of any previous toss. if all tosses are to be heads/tails then each toss you multiply by the number of chances. i,e. 2, starting with 1. three heads in a row is 1x2x2

For 4 coin tosses, there are 16 possible outcomes. Tails on 75% of 4 tosses is 3 times tails, and 1 time heads. This occurs in 4 of those 16 possibilities, so the probability is 4/16 = 1/4 (or 25%). But if the question is 'what is the probability that it's tails at least 75% of the time, then you have to add in the 1 where all 4 are tails, then you have 5/16 (or 31.25%).