The probability that a coin will result in heads in any one toss is 1/2. If you toss the coin three times, the probability that the coin will turn up heads each time is 1/2 x 1/2 x 1/2 or 1/8, which is 12.5%.
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The probability is 0, since there will be some 3-tosses in which you get 0, 1 or 3 heads. So not all 3-tosses will give 2 heads.
With 5 coin tosses there are 32 possible outcomes. 10 of these have exactly 2 heads, and 26 of these have 2 or more heads.For exactly two coins are heads: 10/32 = 31.25%For two or more heads: 26/32 = 81.25%
The chance is 50%-50% that it will be heads or tails; this does not change regardless of the number of previous tosses and their results.
For each toss, the probability that it'll land heads up is 1/2 So 1/2 * 1/2 * 1/2 = 1/8, or .125 There is a 12.5% chance that it will land heads-up all 3 times.
To find P( at least 1 head in 7 tosses) we can find P( no heads) and subtract that from one. Alternatively, we need to find P ( 1 head) + P ( 2 heads )+...+ P(7 heads) Since P of no heads is P( all tails) this is (1/2)7 =.0078125 ( 1/128 as a fraction) Now 1-(1/128)=127/128 or .9921875