one fourth
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2/8 or 1/4 or 25 %
If both tosses are fair, the probability of that outcome is one in four.
It is 0.375It is 0.375It is 0.375It is 0.375
This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %
1 in two but they say the side with heads is slightly Heavier.