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What is the probability if 8 coins are flipped exactly 2 coins will show heads?
2/8 or 1/4 or 25 %
What is the probability of flipping 2 coins and having both show heads?
If both tosses are fair, the probability of that outcome is one in four.
What is the probability of tossing three coins and having them exactly one of them show tails?
It is 0.375It is 0.375It is 0.375It is 0.375
When tossing 5 coins simultaneously find the probability that at least 1 head is showing.?
This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %
What are the odds agains two coins landing on heads?
When flipping two fair coins, each coin has a 50% chance of landing on heads. The probability of both coins landing on heads is calculated by multiplying the probabilities of each coin: (0.5 \times 0.5 = 0.25) or 25%. Therefore, the odds against both coins landing on heads are 3 to 1, meaning there are three outcomes (one head and one tail, or two tails) for every one outcome where both coins show heads.
What is the probability if 8 coins are flipped exactly 2 coins will show heads?
2/8 or 1/4 or 25 %
If n coins are tossed simultaneously what is the probability that they are all show heads?
(0.5)n
Three fair coins are tossed at the same time What is the probability that one of the coins will show heads and the other two will show tails?
2/9
What is the probability of flipping 2 coins and having both show heads?
If both tosses are fair, the probability of that outcome is one in four.
What is the probability of tossing three coins and having exactly two of them show tails?
2 out of 8
What is the probability of tossing three coins and having them exactly one of them show tails?
It is 0.375It is 0.375It is 0.375It is 0.375
When tossing 5 coins simultaneously find the probability that at least 1 head is showing.?
This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %
How many times would a coin have to show heads in 50 tosses to show an experimental probability of 20 percent more than the theoretical probability of getting heads?
Theoretical probability = 0.5 Experimental probability = 20% more = 0.6 In 50 tosses, that would imply 30 heads.
What are the odds agains two coins landing on heads?
When flipping two fair coins, each coin has a 50% chance of landing on heads. The probability of both coins landing on heads is calculated by multiplying the probabilities of each coin: (0.5 \times 0.5 = 0.25) or 25%. Therefore, the odds against both coins landing on heads are 3 to 1, meaning there are three outcomes (one head and one tail, or two tails) for every one outcome where both coins show heads.
Two coins and two number cubes are tossed at the same time. What is the approximate probability that the two coins show different sides and the two number cubes show the same number?
It is 1/12.
What is the probability that flipping two coin will show two tails?
1 in two but they say the side with heads is slightly Heavier.
What is the probability that the first two flips will both be heads and the third flip will be either heads or tails if you flip three fair coins?
I assume you mean what's the chance of at least two heads showing when three fair coins are tossed. There are 8 possible outcomes as each coin can either be head or tails. For 3 heads, all 3 coins must show a head → 1 success For 2 heads, one coin will be a Tail; each coin could be a tail in turn → 3 successes → Pr = (1+3)/8 = 4/8 = 1/2 If you are wanting the probability that the first TWO specific coins are heads and the last, third, coin is either, then: Pr(head) = 1/2 → Pr(1st 2 heads, 3rd anything) = 1/2 × 1/2 × 1 = 1/4
