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You want the area under the normal curve between z1 = (36-36.2)/3.7 and z2 = (37.5-36.2)/3.7
Using half tail tables (which give the probability (area under the normal curve) between the mean and z - the number of standard deviations from the mean of the value, negative just means it's to the left of the mean):
z1 = (36 - 36.2) / 3.7 ≈ -0.0541
z2 = (37.5 - 36.2) / 3.7 ≈0.3514
→ area between -0.0541 and 0.3515 standard deviations from the mean
= 0.0199 + 0.1368
= 0.1567
= 15.67 %
What else can I help you with?
The miles per gallon for a mid-size car is normally distributed with a mean of 32 and a standard deviation of 8 what is the probability that the mpg for a selected mid-size car would be less than 33.2?
The MPG (mileage per gallon) for a mid-size car is normally distributed with a mean of 32 and a standard deviation of .8. What is the probability that the MPG for a selected mid-size car would be less than 33.2?
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The answer depends on how the sample is selected. If it is a simple random sample, of size n, then it is distributed approximately normally with the same mean as the population mean.The answer depends on how the sample is selected. If it is a simple random sample, of size n, then it is distributed approximately normally with the same mean as the population mean.The answer depends on how the sample is selected. If it is a simple random sample, of size n, then it is distributed approximately normally with the same mean as the population mean.The answer depends on how the sample is selected. If it is a simple random sample, of size n, then it is distributed approximately normally with the same mean as the population mean.
Assume that women's heights are normally distributed with a mean given by mu equals 63.6 in and a standard deviation given by sigma equals 2.1 in (a) If 1 woman is randomly selected find the probabili?
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The miles per gallon for a mid-size car is normally distributed with a mean of 32 and a standard deviation of 8 what is the probability that the mpg for a selected mid-size car would be less than 33.2?
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What is the probability that a randomly selected case from a normally distributed distribution will have a score between -1.00 and the mean?
The answer is 0.1586
Are normally distributed with a mean of 68 inches and a standard deviation of 2 inches What is the probability that the height of a randomly selected female college basketball player is more than 66?
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A bank and loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50. If an applicant is randomly selected find the probabili?
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When you draw a sample from a normal distribution what can you conclude about the sample distribution?
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Assume that women's heights are normally distributed with a mean given by mu equals 63.6 in and a standard deviation given by sigma equals 2.1 in (a) If 1 woman is randomly selected find the probabili?
To find the probability of a randomly selected woman having a height within a specific range, we can use the normal distribution with the given mean (μ = 63.6 inches) and standard deviation (σ = 2.1 inches). For instance, if we want to find the probability that a randomly selected woman is shorter than 65 inches, we would calculate the z-score using the formula ( z = \frac{(X - \mu)}{\sigma} ), where ( X ) is the height in question. After calculating the z-score, we would consult the standard normal distribution table or use a calculator to find the corresponding probability. If you have a specific height range in mind, please specify for a more detailed calculation.
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0.9699
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