The probability is1 - [Prob(No children) + Prob(1 child, a girl) + Prob(2 children, both girls) + Prob(3 children, all girls) + ...]Not all relevant information is readily available.
Assuming that children of either gender are equally likely, the answer is (1/2)3 = 1/8
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of the other two being boys is 0.2672.
The answer is that they are all girls. All 5 children
It is not possible to give a proper answer to the question for two main reasons. The first reason is that the probability of boys and girls are not equal. The global probability, at birth is 0.517 for boys and 0.483 for girls. Second, the children's genders are not independent events. Third, the gender ratios change with the parents' (mother's) age. If you choose to ignore all these facts, then the probability is (1/2)4 = 1/16
The probably of four girls in a family with four children is 1/16. I got this answer because: Probability of a girl is 1/2 and to get all girls you would multiply it by 1/2 for the rest of the girls.
The probability is1 - [Prob(No children) + Prob(1 child, a girl) + Prob(2 children, both girls) + Prob(3 children, all girls) + ...]Not all relevant information is readily available.
4/6=2/4 n(s)=3 6
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52 in all cases, the overall probability is 0.0624.
It is difficult to answer this question properly. One reason is that children's genders are not independent of one another: the gender depends on the parents' genetics and their age. The second reason is that the probability of a girl is not 0.50 but approx 0.48. However, if you ignore reality, then the answer is (1/2)4 = 1/16
Assuming that children of either gender are equally likely, the answer is (1/2)3 = 1/8
The genders of children within the same family are not independent. So the answer will depends on the pattern of children's gender in the family's ancestry, as well as the age of the parents. However, if you make the unreasonable and unjustified assumption that the genders are independent and that the probability of either gender is 1/2, then the answer is (1/2)5 = 1/32.
There is no simple answer.First of all, the probability of boys is 0.517 not0.5.Second, the probabilities are not independent.If you choose to ignore these important facts, then the answer is 2/3.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of the other two being boys is 0.2672.
yes all of Winston churchill's children were girls
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
The answer is that they are all girls. All 5 children