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I Assume you mean two separate dice rolls.

There are 2 possible chances to get 5 or higher in the first roll: 5 or 6. So, if you roll one of those, the second roll is irrelevant. So, thus far, we have a (2/6)*(6/6) chance = 12/36. If you miss it the first roll, meaning you rolled a 1-4, then the second roll has to be a 5 or 6. So there is a 4/6 chance of rolling 1-4 and a 2/6 chance of then rolling a 5 or 6. (4/6)*(2/6) = 8/36

So your total probability is 12/36 + 8/36 = 20/36 = 5/9

I bet you thought it was going to be 2/3 :)

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14y ago

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