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If the order of the numbers matters, then:

The probability of a 6 on the first roll is 1/6.

The probability of a 1 on the second roll is 1/6.

The probability of a 3 on the third roll is 1/6.

The probability of all three is (1/6 x 1/6 x 1/6) = 1/216 = 0.00463 = 0.463 % (rounded)

If you're not concerned about the order of the rolls, only the probability of getting all three numbers, then:

The probability of getting any one of them on the first roll is 3/6, or 1/2.

The probability of getting one of the other two on the second roll is 2/6, or 1/3.

The probability of getting the final one on the third roll is 1/6.

The chance of all three without order then is (1/2 x 1/3 x 1/6) = 1/36 or 2.778% (rounded)

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Q: What is the probability that you roll a six and one and three?
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