If the order of the numbers matters, then:
The probability of a 6 on the first roll is 1/6.
The probability of a 1 on the second roll is 1/6.
The probability of a 3 on the third roll is 1/6.
The probability of all three is (1/6 x 1/6 x 1/6) = 1/216 = 0.00463 = 0.463 % (rounded)
If you're not concerned about the order of the rolls, only the probability of getting all three numbers, then:
The probability of getting any one of them on the first roll is 3/6, or 1/2.
The probability of getting one of the other two on the second roll is 2/6, or 1/3.
The probability of getting the final one on the third roll is 1/6.
The chance of all three without order then is (1/2 x 1/3 x 1/6) = 1/36 or 2.778% (rounded)
The probability that when you roll three dice you will get exactly one six is; P(one 6) = 3C1∙(1/6)∙(5/6)2= 0.347222... ~ 34.7% where 3C1= 3!/[1!∙(3-2)!] = 3, are the three ways the six can come out, that is the six can come out from die one, die two or die three.
The probability that a six will never show up in three rolls of a die is 125 in 216. The probability that a six will not show up in one roll is 5 in 6. Raise that to the third power to get 125 in 216.
If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.
The probability of rolling any single number of a regular die on one roll is one in six, or 1/6, or 0.166666....
The probability of rolling either a 6 or 4 on one roll of a dice is two thirds (one sixth plus one sixth because both four and six have a probability of one sixth.
The probability that when you roll three dice you will get exactly one six is; P(one 6) = 3C1∙(1/6)∙(5/6)2= 0.347222... ~ 34.7% where 3C1= 3!/[1!∙(3-2)!] = 3, are the three ways the six can come out, that is the six can come out from die one, die two or die three.
The probability that a six will never show up in three rolls of a die is 125 in 216. The probability that a six will not show up in one roll is 5 in 6. Raise that to the third power to get 125 in 216.
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
There is one three on a dice, and there are six sides, so the probability of rolling a three is 1 out of 6 or about 16.6%.
1/6
If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.
I'm assuming you're looking for the probability that you roll either a one or six at least once. So the problem can be rewritten as: 1 - probability of rolling 60 times and never getting ones or sixes = 1 - (2/3)^60
The probability of rolling any single number of a regular die on one roll is one in six, or 1/6, or 0.166666....
The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.
The probability of rolling either a 6 or 4 on one roll of a dice is two thirds (one sixth plus one sixth because both four and six have a probability of one sixth.
One roll of one normal cube: the answer is 0.
One in 6. In a six side die