If the order of the numbers matters, then:
The probability of a 6 on the first roll is 1/6.
The probability of a 1 on the second roll is 1/6.
The probability of a 3 on the third roll is 1/6.
The probability of all three is (1/6 x 1/6 x 1/6) = 1/216 = 0.00463 = 0.463 % (rounded)
If you're not concerned about the order of the rolls, only the probability of getting all three numbers, then:
The probability of getting any one of them on the first roll is 3/6, or 1/2.
The probability of getting one of the other two on the second roll is 2/6, or 1/3.
The probability of getting the final one on the third roll is 1/6.
The chance of all three without order then is (1/2 x 1/3 x 1/6) = 1/36 or 2.778% (rounded)
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The probability that when you roll three dice you will get exactly one six is; P(one 6) = 3C1∙(1/6)∙(5/6)2= 0.347222... ~ 34.7% where 3C1= 3!/[1!∙(3-2)!] = 3, are the three ways the six can come out, that is the six can come out from die one, die two or die three.
The probability that a six will never show up in three rolls of a die is 125 in 216. The probability that a six will not show up in one roll is 5 in 6. Raise that to the third power to get 125 in 216.
If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.
The probability of rolling any single number of a regular die on one roll is one in six, or 1/6, or 0.166666....
The probability of rolling either a 6 or 4 on one roll of a dice is two thirds (one sixth plus one sixth because both four and six have a probability of one sixth.