I'm assuming you're looking for the probability that you roll either a one or six at least once. So the problem can be rewritten as:
1 - probability of rolling 60 times and never getting ones or sixes
= 1 - (2/3)^60
The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.
You add the probabilities together. For each roll, it is 1/6; therefore, you will have 60 times 1/6, which is 60/6, which is 10. Since probability is only 1 at the most, which means that it WILL happen, I would say that the probability is 1 (or 100%).
The probability of 1 roll of 4 rolls of a die being 6 is: 1/6 x 5/6 x 5/6 x 5/6 = 125/1296 However, that one roll could be the first, second, third or fourth roll, so the total probability is 4 times this: Pr(one 6 on 4 rolls of 1 die) = 4 x 125/1296 = 125/324 ≈ 0.385
The probability of rolling a 6 on each roll of an unbiased cuboid die is 1/6 If you mean at least one of the rolls shows a 6 then it is the same as 1 - pr(no roll shows a 6) = 1 - (5/6)⁶⁰ ≈ 1 - 0.0000177 = 0.9999823 If you mean that exactly one 6 is rolled then: Pr(exactly one 6) = 60 × 1/6 × (5/6)⁵⁹ ≈ 0.0002130
2 in 6, or 1 in 3, or about 0.3333.
The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.
If you were really unlucky, infinitely many times! The probability of that happening is very tiny but it is not zero.
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
You add the probabilities together. For each roll, it is 1/6; therefore, you will have 60 times 1/6, which is 60/6, which is 10. Since probability is only 1 at the most, which means that it WILL happen, I would say that the probability is 1 (or 100%).
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
One sixth
one out of 6
The probability of rolling a four on a 6-sided die is 1 in 6, or approximately 16.67%. Since the die has 6 equally likely outcomes (the numbers 1 to 6), and only one of those outcomes is a four, the probability is 1/6.
1 out of 6 times,or 16.67% probability.
Since there are 6 sides to the die, the probability of rolling a 5 on one roll is 1/6. Since each roll is an independent event the probability of the multiple results is the product of the probability of each result. So 2 consecutive 5's would occur with a probability of (1/6)(1/6) = 1/36
If you rolled a die 120 times, the probability of getting a 6 is one in six. It does not matter how many times you roll the die - the probability is still one in six - except that the long term mean will approach the theoretical value of 0.166... as the number of trials increases.
The probability that a six will never show up in three rolls of a die is 125 in 216. The probability that a six will not show up in one roll is 5 in 6. Raise that to the third power to get 125 in 216.