the 5 on the die would be 1/6 if the die has the numbers 1-6 on it because each number has an equal chance of being landed on. for tails on a coin it would be 1/2 because both sides have an equal chance of being landed on.
It is 0.5 becasue the events are (or should be) independent.
3/16
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
To find the probability of spinning a number greater than 5 on a spinner numbered 1 to 8, we note that the numbers greater than 5 are 6, 7, and 8, giving us 3 favorable outcomes out of 8 total outcomes. Thus, the probability of this event is 3/8. For the coin toss, the probability of getting a tail is 1/2. The combined probability of both events occurring is (3/8) × (1/2) = 3/16.
One in six. One in two.
It is 0.5 becasue the events are (or should be) independent.
9/2
Firstly, the probability when tossing a coin and getting a head or tail is 1/2, then rolling a die, there are 6 sides so the chance of rolling any number is 1/6, there are 2 chances of rolling greater than 4 ie 5 and 6, so the probability of rolling a 5 or 6 in 1/3, as these are independent events you multiply the probability getting a heads of tails, (1/2) by the probability of rolling a five or six, (1/3) which gives you 1/6 or 0.1666 recurring.
3/16
1/12 (1/6 chance of a 5 * 1/2 chance of getting tails)
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
One in six. One in two.
To find the probability of rolling a 5 on a die and then tossing tails on a coin, we first determine the individual probabilities. The probability of rolling a 5 on a standard six-sided die is ( \frac{1}{6} ), and the probability of tossing tails on a coin is ( \frac{1}{2} ). Since these two events are independent, we multiply their probabilities: [ P(5 \text{ and tails}) = P(5) \times P(tails) = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}. ] Thus, the probability of rolling a 5 and then tossing tails is ( \frac{1}{12} ).
If it is a fair coin, the probability is exactly 50%. The coin has no memory of what it did in the last flip. ■
The probability is 1 out of 5
50-5-