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Subjects>Math>Statistics

What is the probability of obtaining exactly four tails in five flips?

Anonymous

∙ 12y ago

Updated: 4/28/2022

Assume the coin is fair, so there are equal amount of probabilities for the choices.

There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.

Use Binomial to work out this problem. You should get:

(5 choose 4)(½)4(½).

(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.
(½)4 indicates the probability of obtaining 4 tails.
(½) indicates the probability of obtaining the remaining number of head.

Therefore, the probability is 5/32.

Wiki User

∙ 12y ago

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Q: What is the probability of obtaining exactly four tails in five flips?

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Continue Learning about Statistics

What is the probability of obtaining exactly 4 tails from the 9 flips of the coin?

It is approx 0.2461

Suppose that you toss a coin and roll and die What is the probability of obtaining tails?

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Related Questions

What is the probability of obtaining exactly 4 tails from the 9 flips of the coin?

It is approx 0.2461

What is the probability of obtaining exactly two heads in three flips of a coin given that at least one is a head?

The probability of obtaining exactly two heads in three flips of a coin is 0.5x0.5x0.5 (for the probabilities) x3 (for the number of ways it could happen). This is 0.375. However, we are told that at least one is a head, so the probability that we got 3 tails was impossible. This probability is 0.53 or 0.125. To deduct this we need to divide the probability we have by 1-0.125 0.375/(1-0.125) = approximately 0.4286

What is the probability of obtaining exactly four tails in five flips of a coin if at least three are tails?

We need to determine the separate event. Let A = obtaining four tails in five flips of coin Let B = obtaining at least three tails in five flips of coin Apply Binomial Theorem for this problem, and we have: P(A | B) = P(A ∩ B) / P(B) P(A | B) means the probability of "given event B, or if event B occurs, then event A occurs." P(A ∩ B) means the probability in which both event B and event A occur at a same time. P(B) means the probability of event B occurs. Work out each term... P(B) = (5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0 It's obvious that P(A ∩ B) = (5 choose 4)(½)4(½) since A ∩ B represents events A and B occurring at the same time, so there must be four tails occurring in five flips of coin. Hence, you should get: P(A | B) = P(A ∩ B) / P(B) = ((5 choose 4)(½)4(½))/((5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0)

What is the probability of obtaining four tails in five flips of a coin?

Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is Â½. Similarly, the probability of getting a tail is Â½.Use Binomial to work out this problem. You should get:(5 choose 4)(Â½)4(Â½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(Â½)4 indicates the probability of obtaining 4 tails.(Â½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.

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Suppose that you toss a coin and roll and die What is the probability of obtaining tails?

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What is the probability of obtaining tails or a five (Enter the probability as a fraction.)?

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What is the expected number of flips of a coin to simulate a six-sided die?

Five coin flips. Any outcome on a six-sided die has a probability of 1 in 6. If I assume that the order of the outcome does not matter, the same probability can be achieved with five flips of the coin. The possible outcomes of five flips of a coin are as follows: 5 Heads 5 Tails 4 Heads and 1 Tails 4 Tails and 1 Heads 3 Heads and 2 Tails 3 Tails and 2 Heads For six possible outcomes.

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