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-t + 9 = t + 5(if it helps, you can pretend there is a 1 in front of each t)-1t + 9 = 1t + 5Add 1t to both sides-1t + 1t + 9 = 1t + 1t + 5(Keep the variable on the left of the equals sign lessens confusion, so let's flip the terms)9 = 2t + 52t + 5 = 9Subtract 5 from both sides2t + 5 - 5 = 9 - 5Divide both sides by 22/2t = 4/2t = 2
The relationship between Celsius and Fahrenheit is:c = (5 / 9) * (f - 32)So if they are equal, we can simply note that c and f are equal in that equation, and then solve it. Let' call them both "t":t = (5 / 9) * (t - 32)∴ t = (5t - 160) / 9∴ t = 5t/9 - 160/9∴ t - 5t/9 = -160/9∴ 4t/9 = -160/9∴ 4t = -160∴ t = -40So -40°F = -40°C
The temperature T in degrees Celsius (°C) is equal to the temperature T in degrees Fahrenheit (°F) minus 32, times 5/9: T(°C) = (T(°F) - 32) × 5/9 Convert 68 degrees Fahrenheit to degrees Celsius: T(°C) = (68°F - 32) × 5/9 = 20 °C
-5*3/4+t=-9 4/5 -15/4+t=-49/5 t = -196/20 + 75/20 t = -121/20
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T in C = ( T in F - 32.0 ) ( 5/9 )T in C = ( 15 - 32.0 ) ( 5/9 ) = -9.4 C
9(5+t) < 6 or simplified 45 + 9t < 6 then 9t< -39 and t < -39/9 = t < -13/3
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the answer is 9(5+t)<6 <3 you
-t + 9 = t + 5(if it helps, you can pretend there is a 1 in front of each t)-1t + 9 = 1t + 5Add 1t to both sides-1t + 1t + 9 = 1t + 1t + 5(Keep the variable on the left of the equals sign lessens confusion, so let's flip the terms)9 = 2t + 52t + 5 = 9Subtract 5 from both sides2t + 5 - 5 = 9 - 5Divide both sides by 22/2t = 4/2t = 2
t(1)= = 9*1 - 3 = 9 - 3 = 6 t(2)= = 9*2 - 3 = 18 - 3 = 15 t(3)= = 9*3 - 3 = 27 - 3 = 24 t(4)= = 9*4 - 3 = 36 - 3 = 33 t(5)= = 9*5 - 3 = 45 - 3 = 42
9 = T+4Take 4 from both sides9(-4) = T(-4)5=T:)
The relationship between Celsius and Fahrenheit is:c = (5 / 9) * (f - 32)So if they are equal, we can simply note that c and f are equal in that equation, and then solve it. Let' call them both "t":t = (5 / 9) * (t - 32)∴ t = (5t - 160) / 9∴ t = 5t/9 - 160/9∴ t - 5t/9 = -160/9∴ 4t/9 = -160/9∴ 4t = -160∴ t = -40So -40°F = -40°C
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The temperature T in degrees Celsius (°C) is equal to the temperature T in degrees Fahrenheit (°F) minus 32, times 5/9: T(°C) = (T(°F) - 32) × 5/9 Convert 68 degrees Fahrenheit to degrees Celsius: T(°C) = (68°F - 32) × 5/9 = 20 °C
LCM of 5,9 = 45