Their average is 22 and their difference is 9 so use 22 and 9 13*31 = 222 - 92 = 484 - 81 = 403
52 = 2 x 2 x 13 OR 22 x 13
You need to look for 2 numbers which have a product of 156 and a difference of 1. First 156 can be written as a product of it's prime factors: 156 = 22 x 3 x 13. From this you can see that 22 x 3 = 12 and hence 12 x 13 = 156.
Both of these:52 = 2 x 2 x 1352 = 22 x 13
As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39
Their product.
13
9 and 13
They are 9 and 13
9 and 13
35
66/5 or 13 and 1/5
Their average is 22 and their difference is 9 so use 22 and 9 13*31 = 222 - 92 = 484 - 81 = 403
52 = 2 x 2 x 13 OR 22 x 13
22% of 13= 22% * 13= 0.22 * 13= 2.86
Let the two numbers be a & b. Then ab = 22 therefore b = 22/a And, a + b = 13 . . . after substituting for b this becomes a + (22/a) = 13 . . . multiply throughout by a. a2 + 22 = 13a a2 - 13a + 22 = 0 . . . this can be factored (a - 2)(a - 11) = 0 . . .thus a = 2 or 11 and so b = 11 or 2. The two numbers are 2 and 11.
You need to look for 2 numbers which have a product of 156 and a difference of 1. First 156 can be written as a product of it's prime factors: 156 = 22 x 3 x 13. From this you can see that 22 x 3 = 12 and hence 12 x 13 = 156.