Let the two numbers be a & b.
Then ab = 22 therefore b = 22/a
And, a + b = 13 . . . after substituting for b this becomes
a + (22/a) = 13 . . . multiply throughout by a.
a2 + 22 = 13a
a2 - 13a + 22 = 0 . . . this can be factored
(a - 2)(a - 11) = 0 . . .thus a = 2 or 11 and so b = 11 or 2.
The two numbers are 2 and 11.
9 and 13
Let's denote the two numbers as x and y. We know that x + y = 22 and x * y = 117. By solving these two equations simultaneously, we can find that the two numbers are 9 and 13. This is because 9 + 13 = 22 and 9 * 13 = 117.
9 13
9 and 13. sorry dont know what i was thinking before.
13 and 22
9 and 13
They are 9 and 13
35
The product is 1254. The sum is 79.
The two numbers are 9 and 13.
9 + 13 = 22
Let's denote the two numbers as x and y. We know that x + y = 22 and x * y = 117. By solving these two equations simultaneously, we can find that the two numbers are 9 and 13. This is because 9 + 13 = 22 and 9 * 13 = 117.
9+13=22 13-9=4
13 and 9 13+9=22 13-9=4
13 and 9
9 13
13&4