the product of -6 and a number, x, decreased by 9, is -33. what is the number?
9y + 7
-3
n*(9 - 2) = 2*7 = 7n
7 and 9 are factors and divisors of 63 63 is a multiple and a product of 7 and 9 63 is divisible by 7 and 9
the product of -6 and a number, x, decreased by 9, is -33. what is the number?
9y + 7
9x = 63 63/9 = 7 Therefore, x = 7
7 and 9 are factors and divisors of 63. 63 is a multiple and product of 7 and 9. 63 is divisible by 7 and 9.
-3
2x + 9 = -17 2x = -26 x = -13
n*(9 - 2) = 2*7 = 7n
7 and 9 are factors and divisors of 63 63 is a multiple and a product of 7 and 9 63 is divisible by 7 and 9
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
7 and 11, 9 and 10
Product of 9 and 7
7 x 9 = 63 7 is a FACTOR of 63 9 is a FACTOR of 63 7 and 9 are even DIVISORS of 63 63 is a MULTIPLE of 7 and 9 63 is a PRODUCT of 7 and 9 63 is evenly DIVISIBLE by 7 or 9