Two negative consecutive odd integers that have a product of 63 are -7 and -9.
-7 is larger than -9.
-7 is the answer.
-7
-1
They are 6, 8, 10 and 12.
One possible answer is -4 and -3.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
-7
-1
They are 6, 8, 10 and 12.
One possible answer is -4 and -3.
4,6,8,10
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
the sum of two consecutive integers is -241, what is the larger integer?
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).
There are no such integers.
The larger number is 20.