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product = 6 first three positive counting numbers = 1, 2, 3
product of the first three positive counting numbers:
1 x 2 x 3 = 6
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What is the product of the first 8 counting numbers?
1x2x3x4x5x6x7x8 = 8! = 40320
Why does the product of 4 negative numbers equal a positive?
If you know that the product of 2 negative numbers is positive, then the product of 4 negative numbers has to be positive. The product of the first two negative numbers is positive and the next two negative numbers is positive. Multiplying the product of the first two numbers (positive number) and the product of the last two numbers (also positive), is a positive number times a positive number which is positive. Let a, b, c and d be negative numbers: (a*b*c*d) = (a*b)*(c*d) (-ve*-ve*-ve*-ve)=(-ve*-ve)*(-ve*-ve)= (+ve)*(+ve) = (+ve)
What is the product of the first six counting numbers?
The product of the first six counting numbers (1, 2, 3, 4, 5, 6) is calculated by multiplying them together: 1 x 2 x 3 x 4 x 5 x 6 = 720. This can be understood as finding the factorial of 6, denoted as 6!. The factorial of a number is the product of all positive integers up to that number.
What is the sum of the first six counting numbers?
The sum of the first six counting numbers (1-6) is 19.
What are the first eight counting numbers?
1, 2, 3, 4, 5, 6, 7, 8, I am counting to the first 8 numbers
