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Label the triangle ABC.

Draw the bisector of angle A to meet BC at D.

Then in triangles ABD and ACD,

angle ABD = angle ACD (equiangular triangle)

angle BAD = angle CAD (AD is angle bisector)

so angle ADB = angle ACD (third angle of triangles).

Also AD is common.

So, by ASA, triangle ABD is congruent to triangle ACD

and therefore AB = AC.

By drawing the bisector of angle B, it can be shown that AB = BC.

Therefore, AB = BC = AC ie the triangle is equilateral.

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12y ago

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