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You could try the fact that the altitude of an equilateral traingle is also its median so that it divides the base in half. Then Pythagoras does the rest.

Q: What is the proof that sine 60 is square root of 3 divided by 2?

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sine[theta]=opposite/hypotenuse=square root of (1-[cos[theta]]^2)

sin2x is the conventional way of writing (sinx)2; it does not denote the sine of sinx as one might expect. So the square root is just sinx.

Every irrational number fits this category. Examples are pi, e, square root of 3, sine of 1.

* subtract * solve * scalene (type of triangle) * square * square root * sum * six * seven * square feet * symmetry * symbol * set * sub set * sine

It is 1.

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For a sine wave, the RMS is the amplitude divided by square root of 2. The amplitude is 10 cm. in this case; so the exact value is 10 / root(2), or about 7.For a sine wave, the RMS is the amplitude divided by square root of 2. The amplitude is 10 cm. in this case; so the exact value is 10 / root(2), or about 7.For a sine wave, the RMS is the amplitude divided by square root of 2. The amplitude is 10 cm. in this case; so the exact value is 10 / root(2), or about 7.For a sine wave, the RMS is the amplitude divided by square root of 2. The amplitude is 10 cm. in this case; so the exact value is 10 / root(2), or about 7.

sine[theta]=opposite/hypotenuse=square root of (1-[cos[theta]]^2)

The square root of two over two.

one over root of 2 or (1/square root of 2) or 1/1.414213562 or 0.707106781

sin2x is the conventional way of writing (sinx)2; it does not denote the sine of sinx as one might expect. So the square root is just sinx.

the square root of 36 times the sine, in radians, of pi/2

The RMS value in this case is the amplitude divided by the square root of 2. Approximately 0.7 times the amplitude.

A square wave has the highest RMS value. RMS value is simply root-mean-square, and since the square wave spends all of its time at one or the other peak value, then the RMS value is simply the peak value. If you want to quantify the RMS value of other waveforms, then you need to take the RMS of a series of equally spaced samples. You can use calculus to do this, or, for certain waveforms, you can use Cartwright, Kenneth V. 2007. In summary, the RMS value of a square wave of peak value a is a; the RMS value of a sine wave of peak value a is a divided by square root of 2; and the RMS value of a sawtooth wave of peak value a is a divided by cube root of 3; so, in order of decreasing RMS value, you have the square wave, the sine wave, and the sawtooth wave. For more information, please see the Related Link below.

RMS stands for Root Mean Square. Power is calculated as V2/R where V is the voltage and R is the resistive component of a load, This is easy toi calculate for a DC voltage, but how to calculate it for a sinusoidal voltage? The answer is to take all the instantaneous voltages in the sine wave, square them, take the mean of the squares, then take the square root of the result. This is defined as the "heating effect voltage". For a sine wave, this is 0.707 of the peak voltage.

Assuming a sine wave, the RMS current (the effective current) is the peak current divided by the square root of 2. In this case, that would be approximately 14 ampere.

Answer #1:The exact value is (square root of 6 + square root of 2) / 4===========================Answer #2:I don't think so.The sine of almost all angles is an irrational number. 75 degrees is one of them.That means its sine can never be exactly written with numbers.The value given in Answer #1 is greater than ' 1 ', and we know that no sine canhave that value.

For an alternating voltage, the simple mean over a cycle would be zero. 'RMS' means 'root mean square', and is defined as the square root of the mean value of the square of the voltage, taken over a cycle. Thus whether the voltage is + or - , as it is in alternate half cycles, the value of its square is always positive, giving a real number for the square root. In fact the RMS value of voltage produces an RMS current which dissipates power at the same rate as a DC current of the same value. To find the RMS value of a sine wave with no DC offset, divide the peak value of the sine wave by square root of 2. **************************************************** Since the r.m.s. value of a sine wave is 1.414Vpk, and the mean voltage of a sine wave is 1.57Vpk, then, starting with the r.m.s. value: Vmean = (Vr.m.s. x 1.414) ÷ 1.57