where ax2 + bx + c = 0
x = [-b +/- √(b2 -4ac)] / 2a
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If the discriminant of the quadratic equation is less than zero then it has no real solutions
what is the process of writing a expression as a product? is it Factoring, Quadractic equation, perfect Square trinomial or difference of two squares
a formula is a formula <3 simples!
5x2 - 3x - 7 = 0 where a = 5, b = -3, and c = -7 x = [-b ± √b2 - 4(a)(c)]/2a x = [-(-3) ± √(-3)2 - 4(5)(-7)]/2(5) x = [3 ± √(9 + 140)]/10 x = (3 ± √149)/10 x = (3 ± 12.21)/10 x = (3 + 12.21)/10 = 15.21/10 = 1.521 or x = (3 - 12.21)/10 = -9.21/10 = -0.921 The EXACT answer would be x = 3/10 ± √149 /10 Note: 149 is not divisable by a perfect square
explain formula transformation