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To use multiplication to check the quotient, you multiply the quotient by the divisor given! For instance: 6 / 2 = 3 Then, to check that 3 is the quotient of 6 and 2, multiply 3 by 2 to get 3 x 2 = 6.
If you mean 6 times x/2 then it is 3x when simplified
2/x
A quotient is the solution to a division sum. Therefore, x/6 = 16. If x/6 = 16 then x = 16 x 6 16 x 6 = 96 Therefore, x = 96.
x/2 = 2x - 3 x = 4x - 6 3x - 6 = 0 3x = 6 x = 2 Check it. 2/2 = 4 - 3 It checks.
To use multiplication to check the quotient, you multiply the quotient by the divisor given! For instance: 6 / 2 = 3 Then, to check that 3 is the quotient of 6 and 2, multiply 3 by 2 to get 3 x 2 = 6.
If you mean 6 times x/2 then it is 3x when simplified
x/6
The quotient of 6 and 3 is 2. 6 (the dividend) divided by 3 (the divisor) equals 2 (the quotient). 6/3=2.
2/x
A quotient is the solution to a division sum. Therefore, x/6 = 16. If x/6 = 16 then x = 16 x 6 16 x 6 = 96 Therefore, x = 96.
x/19 = 6 x = 114
x/2 = 2x - 3 x = 4x - 6 3x - 6 = 0 3x = 6 x = 2 Check it. 2/2 = 4 - 3 It checks.
From the Division Algorithm for Polynomials theorem,f(x) = q(x)g(x) + r(x) or we say:dividend = (quotient)(divisor) + (remainder)In our case,quotient = x^2 - 5x - 6; divisor = x - 3; and remainder = 5.Substitute what you know into the formula, and you will have:f(x) = (x^2 - 5x - 6)(x - 3) + 5f(x) = x^3 - 5x^2 - 6x - 3x^2 + 15x + 18 + 5f(x) = x^3 - 5x^2 - 3x^2 - 6x + 15x + 18 + 5f(x) = x^3 - 8x^2 + 9x + 23 (this is the required polynomial)
x/6 = 29Therefore, x = 6 x 29 = 174
(x/7)2 x= quotient of a number 7= the denominator of x 2 = represents squared
Suppose the two numbers are X and Y and you are given XY = A and X/Y = B. Then AB = XY*X/Y = X2 so that X = sqrt(AB) and A/B = XY / (X/Y) = XY*Y/X = Y2 so that Y = sqrt(A/B) So take the product and quotient that are given. Find THEIR product and quotient. Your two numbers are the square roots of these numbers. Depending on the context (or requirements of the question) you can either use only the principal square roots or select the necassary signs for the square roots. For example, given the product and quotient are 6 and 2/3, AB = 6*2/3 = 4 sand A/B = 6 / (2/3) = 6*3/2 = 9 The possible solutions are X = 2 and Y = 3 OR X = -2 and Y = -3