2m = n/2 - 3 where m and n are the two numbers.
Sum: 16 Product: 48 Difference: 8 Quotient: 3
To use multiplication to check the quotient, you multiply the quotient by the divisor given! For instance: 6 / 2 = 3 Then, to check that 3 is the quotient of 6 and 2, multiply 3 by 2 to get 3 x 2 = 6.
2
Suppose the two numbers are X and Y and you are given XY = A and X/Y = B. Then AB = XY*X/Y = X2 so that X = sqrt(AB) and A/B = XY / (X/Y) = XY*Y/X = Y2 so that Y = sqrt(A/B) So take the product and quotient that are given. Find THEIR product and quotient. Your two numbers are the square roots of these numbers. Depending on the context (or requirements of the question) you can either use only the principal square roots or select the necassary signs for the square roots. For example, given the product and quotient are 6 and 2/3, AB = 6*2/3 = 4 sand A/B = 6 / (2/3) = 6*3/2 = 9 The possible solutions are X = 2 and Y = 3 OR X = -2 and Y = -3
The quotient. In the problem 7 / 2 = 3 (+1) The 7 is the "dividend"; the 2 is the "divisor": the 3 is the "quotient" and the 1 is the "remainder".
1
The answer is 2.
Sum: 16 Product: 48 Difference: 8 Quotient: 3
The quotient of 6 and 3 is 2. 6 (the dividend) divided by 3 (the divisor) equals 2 (the quotient). 6/3=2.
2m = n/2 - 3 where m and n are the two numbers.
Sum: 16 Product: 48 Difference: 8 Quotient: 3
I only know 3. 1) Product Law 2) Quotient Law 3) Pawer Law
3 and 9
One. Uno. Un. 一. um. Yes, it's one.
To use multiplication to check the quotient, you multiply the quotient by the divisor given! For instance: 6 / 2 = 3 Then, to check that 3 is the quotient of 6 and 2, multiply 3 by 2 to get 3 x 2 = 6.
2