Length of arc = pi*radius*angle/180 = 10.47 units (to 2 dp)
If the angle is 2x radians then the length of the arc is 2x*r units where the radius of curvature is r units. If you measure the angle in degrees, then the length of the arc is pi*x*r/90 units.
radius*82*pi/180 units. radius*82*pi/180 units. radius*82*pi/180 units. radius*82*pi/180 units.
Draw a circle with radius of 12 units and draw the horizontal diameter. Draw the perpendicular bisector for this line. Bisect the angle that is formed above the horizontal line. Again, bisect the angle that is formed above the horizontal line: extend this line to the circumference of the circle. This line will be 12 units long because it is a radius of the circle. It is a quarter (half of half) of the 90 degree angle and so the incline is 22.5 degrees.
Area of sector = (32*pi*8.52)/360 = 20.18 square units correct to 2 dp
45.33
6.46
its 45.33 :)..people just need to get straight to the freaking point!
Length of arc = pi*radius*angle/180 = 10.47 units (to 2 dp)
The area of the sector of the circle formed by the central angle is: 37.7 square units.
If the angle is 2x radians then the length of the arc is 2x*r units where the radius of curvature is r units. If you measure the angle in degrees, then the length of the arc is pi*x*r/90 units.
2x*r2 square units where r is the radius and 2x is the angle (measured in radians).
radius*82*pi/180 units. radius*82*pi/180 units. radius*82*pi/180 units. radius*82*pi/180 units.
Area = pi*122 = 144pi square units Shaded area = (260/360)*144pi = 104pi square units
Draw a circle with radius of 12 units and draw the horizontal diameter. Draw the perpendicular bisector for this line. Bisect the angle that is formed above the horizontal line. Again, bisect the angle that is formed above the horizontal line: extend this line to the circumference of the circle. This line will be 12 units long because it is a radius of the circle. It is a quarter (half of half) of the 90 degree angle and so the incline is 22.5 degrees.
Area of sector = (32*pi*8.52)/360 = 20.18 square units correct to 2 dp
For A+ 7.22The area of a sector of a circle is proportional to the angle at the center of the sector, with 360 degrees corresponding to the full circle. Therefore, the area of the total circle for which the problem is stated is 50 X 360/110 = about 163.6 square units. The area of a circle is also equal to pi multiplied by the square of the radius of the circle, so that the radius r of this circle equals the square root of 163.6/pi = about 7.217 units. The circumference of the circle is also twice the radius multiplied by pi = 45 units, to the justified number of significant digits (limited by "50").a+ 45.33