To find the radius of a circle given a 110-degree central angle and an arc length of 50 units, you can use the formula for arc length: ( L = r \theta ), where ( L ) is the arc length, ( r ) is the radius, and ( \theta ) is the angle in radians. First, convert 110 degrees to radians: ( \theta = \frac{110 \times \pi}{180} \approx 1.919 ) radians. Then, rearranging the formula gives ( r = \frac{L}{\theta} = \frac{50}{1.919} \approx 26.0 ) units. So, the radius is approximately 26.0 units.
Length of arc = pi*radius*angle/180 = 10.47 units (to 2 dp)
If the angle is 2x radians then the length of the arc is 2x*r units where the radius of curvature is r units. If you measure the angle in degrees, then the length of the arc is pi*x*r/90 units.
To find the central angle in radians for a sector, you can use the formula for the area of a sector: ( A = \frac{1}{2} r^2 \theta ), where ( A ) is the area, ( r ) is the radius, and ( \theta ) is the central angle in radians. Given that the area ( A = 220 ) square units and the radius ( r = 12 ) units, we can rearrange the formula to solve for ( \theta ): [ \theta = \frac{2A}{r^2} = \frac{2 \times 220}{12^2} = \frac{440}{144} = \frac{55}{18} \text{ radians}. ] Thus, the central angle measures ( \frac{55}{18} ) radians, or approximately 3.06 radians.
radius*82*pi/180 units. radius*82*pi/180 units. radius*82*pi/180 units. radius*82*pi/180 units.
Draw a circle with radius of 12 units and draw the horizontal diameter. Draw the perpendicular bisector for this line. Bisect the angle that is formed above the horizontal line. Again, bisect the angle that is formed above the horizontal line: extend this line to the circumference of the circle. This line will be 12 units long because it is a radius of the circle. It is a quarter (half of half) of the 90 degree angle and so the incline is 22.5 degrees.
45.33
6.46
its 45.33 :)..people just need to get straight to the freaking point!
Length of arc = pi*radius*angle/180 = 10.47 units (to 2 dp)
The area of the sector of the circle formed by the central angle is: 37.7 square units.
If the angle is 2x radians then the length of the arc is 2x*r units where the radius of curvature is r units. If you measure the angle in degrees, then the length of the arc is pi*x*r/90 units.
To find the central angle in radians for a sector, you can use the formula for the area of a sector: ( A = \frac{1}{2} r^2 \theta ), where ( A ) is the area, ( r ) is the radius, and ( \theta ) is the central angle in radians. Given that the area ( A = 220 ) square units and the radius ( r = 12 ) units, we can rearrange the formula to solve for ( \theta ): [ \theta = \frac{2A}{r^2} = \frac{2 \times 220}{12^2} = \frac{440}{144} = \frac{55}{18} \text{ radians}. ] Thus, the central angle measures ( \frac{55}{18} ) radians, or approximately 3.06 radians.
2x*r2 square units where r is the radius and 2x is the angle (measured in radians).
radius*82*pi/180 units. radius*82*pi/180 units. radius*82*pi/180 units. radius*82*pi/180 units.
Draw a circle with radius of 12 units and draw the horizontal diameter. Draw the perpendicular bisector for this line. Bisect the angle that is formed above the horizontal line. Again, bisect the angle that is formed above the horizontal line: extend this line to the circumference of the circle. This line will be 12 units long because it is a radius of the circle. It is a quarter (half of half) of the 90 degree angle and so the incline is 22.5 degrees.
Area = pi*122 = 144pi square units Shaded area = (260/360)*144pi = 104pi square units
Area of sector = (32*pi*8.52)/360 = 20.18 square units correct to 2 dp