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16mm = 1,6 cm.
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
If the circle inscribes the square, the diameter equals the square's side length. In this case, 16mm.
It is: 16mm = 1.6cm
0.63 in.