Divide both by 3 18 / 153 = 6 / 51 then same again 6 / 51 = 2 / 17
The answer is 18C6 which stands for 18!/[6!*(18-6)!] where n! means 1*2*3*...*n. That simplifies to 18*17*16*15*14*13/(6*5*4*3*2*1) = 18564
(6/17) / 2 = 3/17
There are probably tens of such sets. Some are: 5, 6, 7, 7, 8, 11, 13, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 16, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 16, 18
14Another answer:-17+17-14+(2*6)+2 = 0
5/6 + 2/18 = 15/18 + 2/18 = 17/18
1, 17 1, 2, 3, 6, 9, 18
Mean: 16 Median: 17 Mode: 13 Range: 6
To find the range of a group of numbers, subtract the smallest from the largest. examples: * range of {6, 8, 12, 19, 27} is 27 - 6 = 21 * range of {5, -2, 1, 10, 18} is 18 - (-2) = 18 + 2 = 20
1/9 + 5/6 = 6/54 + 45/54 = 51/54 = 17/18
306 = 3*102 = 6*51 = 18*17 The numbers are 17 and 18
6(2 + 1) = 18==========
25/6 * 1/3 = 17/6 * 1/3 = 17/18
I'm guessing that's 8 and 1/9 - 2 and 5/6 which is 73/9 - 17/6 146/18 - 51/18 = 95/18 or 5 and 5/18
1, 2, 3, 6, 9, 18 1, 3, 17, 51
The factors of 18 are: 1, 2, 3, 6, 9, 18 The factors of 34 are: 1, 2, 17, 34 The factors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54
Divide both by 3 18 / 153 = 6 / 51 then same again 6 / 51 = 2 / 17