y = -2x² + x
y = -2 [ x² - (x/2) ]
y = -2 [ x² - (x/2) + (1/4) ] + (1/2)
y = (1/2) - 2[ x - (1/2) ]² ≤ (1/2)
Hence, the Range of y is : -∞ < y ≤ (1/2).
It can be written as the interval ( -∞, 1/2 ]. ........ Ans.
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Negative 11
x is negative 1x is negative 2
8x squared
89
pythagoras
Negative 11
x is negative 1x is negative 2
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
104
y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1
A negative plus a negative equals a negative.
8x squared
negative 2
89
pythagoras
-x2+2.5x+1=0 x=-0.350781 x=2.85078
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.