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y = -2x² + x

y = -2 [ x² - (x/2) ]

y = -2 [ x² - (x/2) + (1/4) ] + (1/2)

y = (1/2) - 2[ x - (1/2) ]² ≤ (1/2)

Hence, the Range of y is : -∞ < y ≤ (1/2).

It can be written as the interval ( -∞, 1/2 ]. ........ Ans.

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13y ago
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Q: What is the range of y equals negative 2x squared plus x?
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