6 m/s divided by 12 s or 0.5 m/s^2. (a half meter per second per second)
(on average)
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
Kilometers/hour2. Note that for this kind of calculation, it is much more common to measure distances in meters, time in seconds, velocity in meters/second, and acceleration in meters/second2.
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Given the initial velocity (A), final velocity (B), and time (8 seconds), you can substitute the values into the formula to find the acceleration.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
The velocity gained by the aircraft in 4 seconds can be calculated using the formula: velocity = acceleration × time. Given acceleration of 3 m/s^2 and time of 4 seconds, the velocity gained by the aircraft would be 12 meters per second.
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
Kilometers/hour2. Note that for this kind of calculation, it is much more common to measure distances in meters, time in seconds, velocity in meters/second, and acceleration in meters/second2.
To determine the velocity of the ball 0.6 seconds after its release, we need more information such as the initial velocity and acceleration of the ball. You would use the formula: velocity = initial velocity + (acceleration * time).
Seconds are not squared in the acceleration formula. The units for acceleration are meters per second squared (m/s^2), where the time unit (seconds) is squared to represent the change in velocity over time.
Acceleration is the rate of change of velocity over time. By dividing a unit of velocity by a unit of time, we can derive the unit of acceleration. For example, if velocity is measured in meters per second (m/s) and time is measured in seconds (s), acceleration would be in meters per second squared (m/s^2).
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
The sprinter's velocity at 1.2 seconds can be calculated using the formula: velocity = initial velocity + acceleration × time. Given the initial velocity is 0 m/s, acceleration is 2.3 m/s^2, and time is 1.2 seconds, the velocity at 1.2 seconds would be 2.76 m/s.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.