ratio would also be 2 since the volume of a sphere is 4/3(pie)r(cubed) and since both 4/3 and pie are constants the variable is the radius of the spheres and as such the ratio of the radii would be equal to that of the volumes.
729/8
The similarity ratio of the two spheres can be found by taking the cube root of the ratio of their volumes. The volume of the first sphere is 20pi m^3 and the volume of the second sphere is 160pi m^3. The cube root of the ratio of their volumes is (160pi/20pi)^(1/3) = (8)^(1/3) = 2. Therefore, the similarity ratio of the two spheres is 2:1.
The circumference of Circle K is ( \pi ), which implies its radius ( r_K ) is ( \frac{1}{2} ). For Circle L, with a circumference of ( 4\pi ), its radius ( r_L ) is ( 2 ). The ratio of their radii is ( \frac{r_K}{r_L} = \frac{1/2}{2} = \frac{1}{4} ). The areas of the circles are proportional to the squares of their radii, so the ratio of their areas is ( \frac{(r_K)^2}{(r_L)^2} = \frac{(1/2)^2}{(2)^2} = \frac{1/4}{4} = \frac{1}{16} ).
They must have all angles which are the same, all of whose straight lines are in the same ratio and whose curves have radii of curvature in the same ratio.
2 radii = one diameter
729/8
It is 8 : 343.
If the ratio is 2 : 7 then the volumes are in the ratio 8 : 343.
The ratio of all lengths is the same. The ratio of the circumferences = ratio of the radii = 2:3
Ratio of volumes is 53 to 83 which is 125 to 512
The similarity ratio of the two spheres can be found by taking the cube root of the ratio of their volumes. The volume of the first sphere is 20pi m^3 and the volume of the second sphere is 160pi m^3. The cube root of the ratio of their volumes is (160pi/20pi)^(1/3) = (8)^(1/3) = 2. Therefore, the similarity ratio of the two spheres is 2:1.
They must have all angles which are the same, all of whose straight lines are in the same ratio and whose curves have radii of curvature in the same ratio.
2 radii = one diameter
The area of a circle is directly proportional to the square of its radius. If two circles have radii R1 and R2 , then the ratio of their areas is ( R1/R2 )2
If two shapes are similar, then each length is in the same ratio. The ratio of the heights is 10 : 2 Thus the radii are in the same ratio, ie 4 : x = 10 : 2 → x = 2 × 4 ÷ 10 = 0.8 units
About 114 lbs at the surface. From Wikipedia, the ratio of the mass of Neptune to the mass of Earth is about 17.15, while the ratio of the radii is about 3.88 (at the equator). The new weight will then be Wneptune = Wearth (17.15) / (3.88^2).
Well, the equation for finding the circumfrence of a circle is (diameter)(pi). That is diameter times pi. since the diameter of a circle is 2 radii, we can say that there is 2(pi) radii in a circle.